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a: \(\Leftrightarrow\left|x-3\right|=12-5x-8=-5x+4\)
\(\Leftrightarrow\left\{{}\begin{matrix}x< =\dfrac{4}{5}\\\left(-5x+4\right)^2=\left(x-3\right)^2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x< =\dfrac{4}{5}\\\left(5x-4-x+3\right)\left(5x-4+x-3\right)=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x< =\dfrac{4}{5}\\\left(4x-1\right)\left(6x-7\right)=0\end{matrix}\right.\Leftrightarrow x=\dfrac{1}{4}\)
b: \(\left(\sqrt{x}+3\right)^{10}=1024\cdot125^2\cdot25^2\)
\(\Leftrightarrow\left(\sqrt{x}+3\right)^{10}=2^{10}\cdot5^6\cdot5^4=10^{10}\)
\(\Leftrightarrow\sqrt{x}+3=10\)
hay x=49
c: \(\dfrac{3-0.2x}{5}=\dfrac{7}{15}+1.4x\)
\(\Leftrightarrow\dfrac{9-0.6x}{15}=\dfrac{7}{15}+\dfrac{21x}{15}\)
=>21x+7=9-0,6x
=>21,6x=-2
hay x=-5/54
d: \(\Leftrightarrow\left(\dfrac{4}{3}\right)^{3x}=\dfrac{5^9\cdot7^9\left(4\cdot7-5^2\right)}{5^9\cdot7^9\cdot4}\)
\(\Leftrightarrow\left(\dfrac{4}{3}\right)^{3x}=\dfrac{28-25}{4}=\dfrac{3}{4}\)
=>3x=-1
hay x=-1/3
Noob ơi, bạn phải đưa vào máy tính ý solve cái là ra x luôn, chỉ tội là đợi hơi lâu
a, 4.(18 - 5x) - 12(3x - 7) = 15(2x - 16) - 6(x + 14)
=> 72 - 20x - 36x + 84 = 30x - 240 - 6x - 84
=> (72 + 84) + (-20x - 36x) = (30x - 6x) + (-240 - 84)
=> 156 - 56x = 24x - 324
=> 24x + 56x = 324 + 156
=> 80x = 480
=> x = 480 : 80 = 6
Vậy x = 6
5\(x\) - 16 = 40 + \(x\)
5\(x\) - \(x\) = 40 + 16
4\(x\) = 56
\(x=56:4\)
\(x=14\)
Vậy \(x=14\)
b; 4\(x\) - 10 = 15 - \(x\)
4\(x\) + \(x\) = 15 +10
5\(x=25\)
\(x=25:5\)
\(x=5\)
Vậy \(x=5\)
c; -12 + \(x\) = 5\(x-20\)
5\(x\) = - 12 + \(x\) + 20
5\(x\) - \(x\) = - 12+ 20
4\(x\) = 8
\(x=\dfrac{8}{4}\)
\(x=2\)
Vậy \(x=2\)
d; \(x+15\) = 7 - 6\(x\)
6\(x\) = 7 - \(x\) - 15
6\(x\) + \(x\) = 7 - 15
7\(x\) = - 8
\(x=-\dfrac{8}{7}\)
Vậy \(x=-\dfrac{8}{7}\)
a) \(1,25:0,8=\frac{3}{8}:0,2x\)
\(\Rightarrow\frac{3}{8}:0,2x=\frac{25}{16}\)
\(\Rightarrow0,2x=\frac{3}{8}:\frac{25}{16}=\frac{6}{25}\)
\(\Rightarrow x=\frac{6}{25}:\frac{1}{5}=\frac{6}{5}\)
b) \(1,8:1,3=\left(-2,7\right):5x\)
\(\Rightarrow\frac{-27}{10}:5x=\frac{18}{13}\)
\(\Rightarrow5x=\frac{-27}{10}:\frac{18}{13}=\frac{-39}{20}\)
\(\Rightarrow x=\frac{-39}{100}\)
a, 4x - 15 = ( -75 ) - x
<=> 4x +x = -75 + 15
<=> 5x = -60
<=> x = -12
b, 72 - 3x = 5x +8
<=> 72 - 8 = 5x + 3x
<=> 8x = 64
<=> x = 8
c, 3.|x-7| = 21
* Nếu x - 7 \(\ge\)0 <=> x \(\ge\)7 thì
PT <=> 3 .( x- 7 ) = 21
<=> x - 7 = 7
<=> x = 14 ( tm )
* Nếu x < 7 <=> x < 7 thì
PT <=> 3. [ - ( x- 7 ) ] = 21
<=> -x +7 = 7
<=> -x = 0
<=> x = 0 ( tm )
d, \(-7.|x+3|=-49\).
\(\Leftrightarrow|x+3|=7\)
\(\Leftrightarrow\orbr{\begin{cases}x+3=7\\x+3=-7\end{cases}\Leftrightarrow\orbr{\begin{cases}x=4\\x=-10\end{cases}}}\)
e, c-12.(x-5)+7.(3-x)=5
<=> -12x + 60 + 21 - 7x = 5
<=> -19x + 81 = 5
<=> -19x = -76
<=> x = 4
a.
\(\left(3x-1\right)\left(2x+7\right)-\left(x+1\right)\left(6x-5\right)=16\)
\(6x^2+21x-2x-7-6x^2+5x-6x+5=16\)
\(\left(6x^2-6x^2\right)+\left(21x-2x+5x-6x\right)-\left(7-5\right)=16\)
\(18x-2=16\)
\(18x=16+2\)
\(18x=18\)
\(x=\frac{18}{18}\)
\(x=1\)
b.
\(\left(10x+9\right)x-\left(5x-1\right)\left(2x+3\right)=8\)
\(10x^2+9x-10x^2-15x+2x+3=8\)
\(\left(10x^2-10x^2\right)-\left(15x-9x-2x\right)+3=8\)
\(-4x=8-3\)
\(-4x=5\)
\(x=-\frac{5}{4}\)
c.
\(\left(3x-5\right)\left(7-5x\right)+\left(5x+2\right)\left(3x-2\right)-2=0\)
\(21x-15x^2-35+25x+15x^2-10x+6x-4-2=0\)
\(\left(15x^2-15x^2\right)+\left(25x+21x-10x+6x\right)-\left(35+4+2\right)=0\)
\(42x=41\)
\(x=\frac{41}{42}\)
Mình làm từ ý b nhá :
b) Ta có : |x| = 2x - 1
\(\Leftrightarrow\orbr{\begin{cases}x=2x-1\\x=1-2x\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x-2x=-1\\x+2x=1\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}-x=-1\\3x=1\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=1\\x=\frac{1}{3}\end{cases}}\)
c) Ta có : |2x - 1| = x + 4
\(\Leftrightarrow\orbr{\begin{cases}2x-1=x+4\\2x-1=-x-4\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x-x=4+1\\2x+x=-4+1\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=5\\3x=-3\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=5\\x=-1\end{cases}}\)
đăng ít 1 thôi bn, nhiều nhất 3 câu 1 lần thôi đăng lắm ngại làm
\(a.12-\left|x-3\right|=5x+\)\(8\)
\(\Leftrightarrow\left|x-3\right|=5x+8-12\)
\(\Leftrightarrow\left|x-3\right|=5x-4\)
\(\Leftrightarrow\orbr{\begin{cases}x-3=5x-4\\x-3=-5x+4\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{1}{4}\\x=\frac{7}{6}\end{cases}}}\)
\(b.3-\frac{0.2x}{5}=\frac{7}{15}+1,4x\)
\(\Leftrightarrow\frac{15-0,2x}{5}=\frac{7+21x}{15}\)
\(\Leftrightarrow15.\left(15-0,2x\right)=5.\left(7+21x\right)\)
\(\Leftrightarrow225-3x=35+105x\)
\(\Leftrightarrow-3x-105x=35-225\)
\(\Leftrightarrow-108x=-190\)
\(\Rightarrow x=\frac{95}{54}\)