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c, =(5x)^3 + (y^2)^ 3 = (5x+y^2)(25x^2 - 5xy^2 + y^4)
d, = (0,5.(a+1))^3-1^3 = ( 0,5(a+1) - 1 ) ( 0,25(a+1) ^2 +a,5(a+1) + 1)
e,2x( x+ 1 ) + 2(x+ 1 ) = 2(x+1)(x+1) = 2(x+1)^2
g, y^2 (x^2 + y) - zx^2 - zy = x^2.y^2 - z.x^2 + y^3 - zy = x^2 (y^2 - z) + y (y^2 -z) = (x^2 +y) (y^2 -z)
h,4.x(x-2y) + 8.y(2y -x) = 4x( x- 2 y ) -8 (x - 2y) = (4x - 8) (x-2y)=4(x-2)(x-2y)
k,=(x+1)(3x(x+1)-5x+7) =(x+1) (3x^2 +3x - 5x + 7)
a) \(x^2-x=\left(x+1\right).x\)
b) \(5x^2.\left(x-2y\right)-15x.\left(x-2y\right)=\left(x-2y\right).\left(5x^2-15x\right)\)= \(\left(x-2y\right).5x.\left(x-3\right)\)
c) \(3.\left(x-y\right)-5x.\left(y-x\right)=3\left(x-y\right)+5x\left(x-y\right)\)= \(\left(x-y\right).\left(3+5x\right)\)
a) \(x^2-x=x\left(x-1\right)\)
b) \(5x^2\left(x-2y\right)-15x\left(x-2y\right)\)\(=\left(x-2y\right)\left(5x^2-15x\right)\)\(=\left(x-2y\right).5x\left(x-3\right)\)
c) \(3\left(x-y\right)-5x\left(y-x\right)\)\(=3\left(x-y\right)+5x\left(x-y\right)\)\(=\left(3+5x\right)\left(x-y\right)\)
chắc chắn là đúng 100% luôn
thấy đúng thì k nha
a) \(x^2-x\)
\(=x\left(x-1\right)\)
b) \(5x^2\left(x-2y\right)-15x\left(x-2y\right)\)
\(=\left(x-2y\right)\left(5x^2-15x\right)\)
\(=\left(x-2y\right).5x.\left(x-3\right)\)
c) \(3\left(x-y\right)-5x\left(y-x\right)\)
\(=3\left(x-y\right)+5x\left(x-y\right)\)
\(=\left(x-y\right)\left(3+5x\right)\)
a)\(x^2-x=x\left(x-1\right)\)
b)\(5x^2\left(x-2y\right)-15x\left(x-2y\right)=x.5x\left(x-2y\right)-3.5x\left(x-2y\right)=5x\left(x-2y\right)\left(x-3\right)\)
c)\(3\left(x-y\right)-5x\left(y-x\right)=3\left(x-y\right)+5x\left[-\left(y-x\right)\right]=3\left(x-y\right)+5x\left(x-y\right)=\left(x-y\right)\left(3+5x\right)\)
a) 2x2-6x-x+3 = 2x(x-3) - (x-3) = (x-3)(2x-1)
b) x2-x-5x+5 = x(x-1) - 5(x-1) = (x-1)(x-5)
c) 5x(x-2y) + 2( x-2y)2 = (x-2y)(5x+2x-2y) = (x-2y)(7x-2y)
chú ý : (A-B)2=(B-A)2
d) 7x(4-y)2 - (4-y)3 = ( 16-8y+y2) (7x-4+y)
a) \(2x^2-7x+3=2x^2-6x-x+3=2x\left(x-3\right)-\left(x-3\right)=\left(x-3\right)\left(2x-1\right)\)
b) \(x^2-6x+5=x^2-5x-x+5=x\left(x-5\right)-\left(x-5\right)=\left(x-5\right)\left(x-1\right)\)
c)\(5x\left(x-2y\right)+2\left(2y-x\right)^2=5x\left(x-2y\right)+2\left(x-2y\right)^2\\ =\left(x-2y\right)\left(5x+2x-4y\right)=\left(x-2y\right)\left(7x-4y\right)\)
d) \(7x\left(y-4\right)^2-\left(4-y\right)^3=7x\left(y-4\right)+\left(y-4\right)^3=\left(y-4\right)\left(7x-y-4\right)\)
a) \(2x\left(x-3\right)^2+5x\left(3-x\right)\)
\(=2x\left(x-3\right)^2-5x\left(x-3\right)\)
\(=\left(x-3\right)\left[2x\left(x-3\right)-5x\right]\)
\(=\left(x-3\right)\left(2x^2-6x-5x\right)\)
\(=\left(x-3\right)\left(2x^2-11x\right)\)
\(=x\left(x-3\right)\left(2x-11\right)\)
b) \(\left(x+3\right)^2-4\left(y^2-2y+1\right)\)
\(=\left(x+3\right)^2-2^2\left(y-1\right)^2\)
\(=\left(x+3\right)^2-\left[2\left(y-1\right)\right]^2\)
\(=\left[\left(x+3\right)-2\left(y-1\right)\right]\left[\left(x+3\right)+2\left(y-1\right)\right]\)
\(=\left(x+3-2y+2\right)\left(x+3+2y-2\right)\)
\(=\left(x-2y+5\right)\left(x+2y+1\right)\)
a) \(2x.\left(x-3\right)^2+5x.\left(-x+3\right)=2x.\left(x-3\right)^2-5x.\left(x-3\right)\)
\(=\left(x-3\right).\left(2x^2-11x\right)=\left(x-3\right).x.\left(2x-11\right)\)
b) \(\left(x+3\right)^2-4.\left(y^2-2y+1\right)=\left(x+3\right)^2-2^2.\left(y-1\right)^2\)
\(=\left(x+3\right)^2-\left[2.\left(y-1\right)\right]^2=\left(x-2y+1\right).\left(x+2y+5\right)\)
a) (x - 3)3 + 3 - x
= (x - 3)3 - (x - 3)
= (x - 3)[(x - 3)2 - 1]
= (x - 3)(x - 3 - 1)(x - 3 + 1)
= (x - 3)(x - 4)(x - 2).
b) 33(2y - 3z) - 15x(2y - 3z)2
= 27(2y - 3z) - 15x(2y - 3z)2
= 3(2y - 3z)[9 - 5x(2y - 3z)]
= 3(2y - 3z)(9 - 10xy + 15xz)
d) 18x2(3 + x) + 3(x + 3)
= (x + 3)(18x2 + 3)
= 3(x + 3)(6x2 + 1).
a, (x-3)\(^3\) + 3-x
= (x-3)\(^3\) - (x-3)
= (x-3)*[(x-3)\(^2\) -1]
= (x-3)* ( x\(^2\) - 6x + 9 -1)
= (x-3)*(x\(^2\) - 6x +8)
= (x-3)*[(x\(^2\) -2x) - (4x - 8)]
= (x-3)*[x(x-2) - 4(x-2)]
= (x-3)*(x-2)*(x-4)
b, 3\(^3\)(2y-3z) - 15x(2y-3z)\(^2\)
= (2y-3z) *[3\(^3\) -15x(2y-3z)]
= (2y - 3z)*(27 -30xy +45xz)
= (2y -3z)*3*(9 -10xy +15xz)
= 3*(2y-3z)*(9-10xy+15xz)
c, đề sai
d, 18x\(^2\)(3+x) + 3(x+3)
= 18x\(^2\)(x+3) +3(x+3)
= (x+3)(18x\(^2\) +3)
= (x+3)*3*[(3x)\(^2\) +1)]
= 3(x+3)*[(3x)\(^2\) +1)]
a) =y^2-(x+3)^2
=(y-x-3)(y+x+3).
b)
=x^2-(y^2+2y+1)
=x^2-(y+1)^2
=(x-y-1)(x+y+1)
c)
=(5x^2-15x)(xy-2y)
=5x(x-3)y(x-2)
=5xy(x-2)(x-3).
a) x2 + 6x + 9 = x2 + 2 . x . 3 + 32 = (x + 3)2
b) 10x – 25 – x2 = -(-10x + 25 +x2) = -(25 – 10x + x2)
= -(52 – 2 . 5 . x – x2) = -(5 – x)2
c) 8x3 - 1/8 = (2x)3 – (1/2)3 = (2x - 1/2)[(2x)2 + 2x . 12 + (1/2)2]
= (2x - 1/2)(4x2 + x + 1/4)
d)1/25x2 – 64y2 = (1/5x)2(1/5x)2- (8y)2 = (1/5x + 8y)(1/5x - 8y)
những bài này dễ lắm bn à, chỉ đơn thuần là áp dụng hđt thui
a) (x+1)(4x-8) =0
x+1=0
x= -1
4x-8 =0
x = 2
b) = 2(x+1)(x+1) = 2(x+1)2
..........................
12.C
13.C