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Đặt S= 1.2 + 2.3 + 3.4 + ...+ 99.100
3S = 1.2.3+2.3.3+3.4.3+...+98.99.3+99.100.3
3S= 1.2.3+2.3(4-1)+3.4(5-2)+...+98.99(100-97)+99.100(101-98)
3S= 1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...-97.98.99+99.100.101-98.99.100
3S = 99.100.101 3S = 3.33.100.101
S=33.100.101= 333300
Bạn rút gọn chéo đi 2 với 2 ,3 với 3 cứ như thế còn mỗi 1/100. k nhé
Đặt A= 1.2+2.3 +.......+99.100
3A= 1.2.3+2.3.4+3.4.3 +......+ 99.100.3
3A= 1.2. (3 - 0) + 2.3.(4 - 1) +3.4. (5 - 2)....... . 99.100. (101 - 98)
3A = (1.2.3 + 2.3.4 + 3.4.5 +...... + 99.100.101) - (0.1.2 + 1.2.3 + 2.3.4 +.......+ 98.99.100)
3A = 99.100.101 - 0.1.2
3A = 999900 - 0
3A= 999900
A= 999900 : 3
A = 333300
A=1.2+2.3+3.4+…+99.100
3A = 1.2.3 + 2.3.3 + ... + 99.100.3
3A = 1.2.3 + 2.3.(4-1) + ... + 99.100.(101-98)
3A = 1.2.3 + 2.3.4 - 1.2.3 + ... + 99.100.101 - 98.99.100
3A = 99.100.101
=> A = \(\frac{99.100.101}{3}\)= 333 300
(870 – 1.2).(870 – 2.3).(870 – 3.4) … (870 – 99.100)
Ta có: 870 = 29.30
Nên suy ra: 870 – 29.30 = 29.30 – 29.30 = 0
G = 0.
k cho mik nha, cô mik giảng vậy
A = 1.2 + 2.3 + 3.4 + ... + 99.100
3A = 1.2.(3-0) + 2.3.(4-1) + 3.4.(5-2) + ... + 99.100.(101-98)
3A = 1.2.3 - 0.1.2 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ... + 99.100.101 - 98.99.100
3A = 99.100.101
A = 33.100.101
A = 333300
A=1.2+2.3+3.4+...+99.100
=>3A=1.2.3+2.3.3+3.4.3+...+99.100.3
=1.2.3+2.3(4-1)+3.4(5-2)+....+99.100(101-98)
=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+99.100.101-98.99.100
=99.100.101=999900
=>A=333300
vậy A=333300
l-i-k-e cho mình nha
3S = 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) +...+ 99.100.(101 - 98)
3S = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 +...+ 99.100.101 - 98.99.100
3S = 99.100.101
3S = 999900
S = 333300
Gọi tổng trên là;A
A=9+99+999+........+999...9(20 số 9)
A=(10-1)+(100-1)+.......+(100...0(20 số 0)-1)
A=10+102+103+........+1020-(1+1+.........+1) 20 số 1
10A=102+103+.........+1021-200
10A-A=1021-10-200+20=1021-190
A=\(\frac{10^{21}-190}{9}\)
\(A=\frac{9}{1.2}+\frac{9}{2.3}+\frac{9}{3.4}+...+\frac{9}{98.99}+\frac{9}{99.100}\)
\(A=\frac{1}{9}.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{98.99}+\frac{1}{99.100}\right)\)
\(A=\frac{1}{9}.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{98}-\frac{1}{99}+\frac{1}{99}-\frac{1}{100}\right)\)
\(A=\frac{1}{9}.\left(1-\frac{1}{100}\right)\)
\(A=\frac{1}{9}.\frac{99}{100}\)
\(A=\frac{11}{100}\)
A = 9/1.2 + 9/2.3 + 9/3.4 +...+ 9/98.99 + 9/99.100
= 9. (1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ... + 1/98 - 1/99 + 1/99 - 1/100)
= 9. (1 - 1/100)
= 9 . 99/100
= 891/100
Ta có: 3A=1.2.3+2.3.3+3.4.3+.....+99.100.3
3A=1.2.3+2.3.(4-1)+3.4..(5-2)+....+99.100.(101-98)
3A=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+....+99.100.101-98.99.100
3A=99.100.101
A=\(\frac{99.100.101}{3}\)
A=333300
Đặt A= 1.2+2.3 +.......+99.100
3A= 1.2.3+2.3.4+3.4.3 +......+ 99.100.3
3A= 1.2. (3 - 0) + 2.3.(4 - 1) +3.4. (5 - 2)....... . 99.100. (101 - 98)
3A = (1.2.3 + 2.3.4 + 3.4.5 +...... + 99.100.101) - (0.1.2 + 1.2.3 + 2.3.4 +.......+ 98.99.100)
3A = 99.100.101 - 0.1.2
3A = 999900 - 0
3A= 999900
A= 999900 : 3
A = 333300