Câu hỏi của Đức Tuấn Trần

Question

A=108/199x107/211 + 108/119*104/211 b=15/19*27/33 + 15/19*19/33 - 15/19-13/33

Nguyen Dinh Duc · Accepted Answer

$A=\frac{108}{199}$x$\left(\frac{107}{211}+\frac{104}{211}\right)$

$A=\frac{108}{199}$x $\frac{211}{211}$

$A=\frac{108}{199}$x 1

$A=\frac{108}{199}$

$B=\frac{15}{19}$x $\left(\frac{27}{33}+\frac{19}{33}-\frac{13}{33}\right)$

$B=\frac{15}{19}$x$1$

$B=\frac{15}{19}$

Câu trả lời:

$A=\frac{108}{199}$x$\left(\frac{107}{211}+\frac{104}{211}\right)$

$A=\frac{108}{199}$x $\frac{211}{211}$

$A=\frac{108}{199}$x 1

$A=\frac{108}{199}$

$B=\frac{15}{19}$x $\left(\frac{27}{33}+\frac{19}{33}-\frac{13}{33}\right)$

$B=\frac{15}{19}$x$1$

$B=\frac{15}{19}$