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\((\frac{3}{5}+\frac{2}{5})+(\frac{4}{7}+\frac{1}{7}+\frac{2}{7})\) ) =1+1=2
c1 {3/4+1/2}*5/7
=5/4*5/7
=25/28
c2 {3/4+1/2}*5/7
= 3/4*5/7+1/2*5/7
=15/28+5/14
=25/28
Cách \(1:\)\(\frac{7}{15}x\frac{4}{9}+\frac{4}{9}x\frac{11}{12}\)
\(=\frac{28}{135}+\frac{11}{27}\)
\(=\frac{28}{135}+\frac{11}{27}\)
\(=\frac{28}{135}+\frac{55}{135}\)
\(=\frac{83}{135}\)
Cách \(2:\)\(\frac{7}{15}x\frac{4}{9}+\frac{4}{9}x\frac{11}{12}\)
\(=\frac{4}{9}x\left(\frac{7}{15}+\frac{11}{12}\right)\)
\(=\frac{4}{9}x\left(\frac{84}{180}+\frac{165}{180}\right)\)
\(=\frac{4}{9}x\frac{83}{60}\)
\(=\frac{83}{165}\)
\(\frac{7}{15}x\frac{4}{9}+\frac{4}{9}x\frac{11}{12}\)
C1 = \(\left(\frac{7}{15}+\frac{11}{12}\right)x\frac{4}{9}\)
= \(\frac{83}{60}x\frac{4}{9}\)
= \(\frac{332}{540}\)
C2 \(\frac{7}{15}x\frac{4}{9}+\frac{4}{9}x\frac{11}{12}\)
= \(\frac{28}{135}+\frac{44}{108}\)
= \(\frac{332}{540}\)
1+2+3+4+5+6+7+8+9:9
=1+2+3+4+5+6+7+8+1
=(1+1)+(2+8)+(3+7)+(4+6)+5
=2+10+10+10+5
=(2+5)+(10+10+10)
=7+30
=37
(3/4 + 1/2) x 5/7=
C1: (3/4+2/4) x 5/7= 5/4 x 5/7
=25/28
C2: (3/4 + 1/2) x 5/7= 3/4 x 5/7 + 1/2 x 5/7