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\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)
\(=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)
\(=\frac{2^{29}.3^{18}.\left(5.2-3^2\right)}{2^{28}.3^{18}.\left(5.3-7.2\right)}\)
\(=\frac{2^{29}.3^{18}.1}{2^{28}.3^{18}.1}\)
\(=2\)
\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)
\(=\frac{5.\left(2^2\right)^{15}.\left(3^2\right)^9-2^2.3^{20}.\left(2^3\right)^9}{5.2^9.2^{19}.3^{19}-7.2^{29}.\left(3^3\right)^6}\)
\(=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)
\(=\frac{5.2^{29}.2.3^{18}-2^{29}.3^{18}.3^2}{5.2^{28}.3^{18}.3-7.2^{28}.2.3^{18}}\)
\(=\frac{2^{29}.3^{18}.\left(5.2-3^2\right)}{2^{28}.3^{18}.\left(5.3-7.2\right)}\)
\(=\frac{2^{29}.3^{18}.\left(10-9\right)}{2^{28}.3^{18}.\left(15-14\right)}\)
\(=\frac{2^{29}.3^{18}}{2^{28}.3^{18}}\)
\(=\frac{2^{28}.2.3^{18}}{2^{28}.3^{18}}\)
\(=2\)
mình chỉ cần đáp án thôi ko cần cách làm nha !!!
Bài 1:
1: \(\dfrac{3}{5}\cdot\dfrac{2}{5}\cdot\dfrac{-3}{4}=-\dfrac{9}{50}\)
2: \(1\dfrac{1}{17}\cdot1\dfrac{1}{24}\cdot\left(-5.1\right)=\dfrac{18}{17}\cdot\dfrac{25}{24}\cdot\dfrac{-51}{10}=\dfrac{-45}{8}\)
\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}=\frac{5.\left(2^2\right)^{15}.\left(3^2\right)^9-2^2.3^{20}.\left(2^3\right)^9}{5.2^9.3^{19}.2^{19}-7.2^{29}.\left(3^3\right)^6}=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}=\frac{3^{18}.\left(5.2^{30}-2^{29}.3^2\right)}{3^{18}.\left(5.2^{28}.3-7.2^{29}\right)}=\frac{2^{28}.\left(5.2\right)}{2^{28}\left(5.3-7.2\right)}=\frac{10}{15-14}=\frac{10}{1}=10\)
Có j sai mong bỏ qua
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Bài giải
\(N=\frac{9\cdot5^{20}\cdot27^9-3\cdot9^{15}\cdot25^9}{7\cdot3^{29}\cdot125^6-3\cdot3^9\cdot15^{19}}=\frac{3^2\cdot5^{20}\cdot\left(3^3\right)^9-3\cdot\left(3^2\right)^{15}\cdot\left(5^2\right)^9}{7\cdot3^{29}\cdot\left(5^3\right)^6-3\cdot3^9\cdot\left(3\cdot5\right)^{19}}=\frac{3^2\cdot5^{20}\cdot3^{27}-3\cdot3^{30}\cdot5^{18}}{7\cdot3^{29}\cdot5^{18}-3^{10}\cdot3^{19}\cdot5^{19}}\)
\(=\frac{3^{29}\cdot5^{20}-3^{31}\cdot5^{18}}{7\cdot3^{29}\cdot5^{18}-3^{29}\cdot5^{19}}=\frac{3^{29}\cdot5^{18}\left(5^2-3^2\right)}{3^{29}\cdot5^{18}\left(7-5\right)}=\frac{25-9}{7-5}=\frac{16}{2}=8\)