Question

[Sách Giáo Khoa]

Làm tính chia :

a) \(\left(6x^2+13x-5\right):\left(2x+5\right)\)

b) \(\left(x^3-3x^2+x-3\right):\left(x-3\right)\)

c) \(\left(2x^4+x^3-5x^2-3x-3\right):\left(x^2-3\right)\)

Answer 1

[Nguyễn Lê Phước Thịnh]

a: \(=\dfrac{6x^2+15x-2x-5}{2x+5}=3x-1\)

b: \(=\dfrac{x^2\left(x+3\right)+\left(x-3\right)}{x-3}=x^2+1\)

c: \(=\dfrac{2x^4-6x^2+x^3-3x+x^2-3}{x^2-3}=2x^2+x+1\)