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19 tháng 3 2022

TN1:

PTHH: FeO + H2 --to--> Fe + H2O

            Fe2O3 + 3H2 --to--> 2Fe + 3H2O

            CuO + H2 --to--> Cu + H2O

=> \(n_{O\left(oxit\right)}=n_{H_2O}=\dfrac{15,3}{18}=0,85\left(mol\right)\)

TN2:

PTHH: FeO + 2HCl --> FeCl2 + H2O

             Fe2O3 + 6HCl --> 2FeCl3 + 3H2O

             CuO + 2HCl --> CuCl2 + H2O

=> \(n_{H_2O}=n_{O\left(oxit\right)}=0,85\left(mol\right)\)

=> nHCl = 1,7 (mol)

Theo ĐLBTKL: moxit + mHCl = mmuối + mH2O

=> 50,8 + 1,7.36,5 = mmuối + 0,85.18

=> mmuối = 97,55 (g)

26 tháng 1 2022

Quy đổi Fe3O4 thành FeO, Fe2O3

\(n_{FeCl_2}=\dfrac{7,62}{127}=0,06\left(mol\right)\)

PTHH: FeO + 2HCl --> FeCl2 + H2O

            0,06<------------0,06

=> \(n_{Fe_2O_3}=\dfrac{9,12-0,06.72}{160}=0,03\left(mol\right)\)

PTHH: Fe2O3 + 6HCl --> 2FeCl3 + 3H2O

             0,03-------------->0,06

=> \(m_{FeCl_3}=0,06.162,5=9,75\left(g\right)\)

27 tháng 9 2016

  nH2O=0.2 
nCuO=x,nAl2O3=y,nFeO=z 
80x + 102y + 72z = 17.86 
x + z =0.2 
135x + 267y + 127z = 33.81 
=> y=0.03 => mAl2O3=3.06g =>D

19 tháng 4 2022

Y là Cu không tan trong dd HCl

Bảo toàn khối lượng: \(m_{O_2}=m_{CuO}-m_{Cu}=m+0,6-m=0,6\left(mol\right)\)

\(\rightarrow n_{O_2}=\dfrac{0,6}{32}=0,01875\left(mol\right)\)

PTHH: 2Cu + O2 --to--> 2CuO

        0,0375<-0,01875

=> mCu = 0,0375.80 = 3 (g)

Ơ mCu > mhh (3 > 1,74) đề sai hả bạn, bạn check lại cho mình :D

24 tháng 3 2022
 The Eiffel Tower
The Eiffel Tower is located in Paris, France. It was constructed between 1887 and 1889 as anentrance way to the 1889 World’s Fair and to celebrate the 100thanniversary of the French Revolution. The Tower was opened to visitors on May 6th, 1889.
Gustave Eiffel’s design was chosen from among 107 designs that were submitted to the World’s Fair design competition. However, many Parisians, especially artists, did not like his design and protested the tower’s construction. They thought it would be an eyesore, but once it was built, most Parisians soon loved the tower.
The tower is made of iron and weighs over 10,000 tons. It is 324 meters tall, including an antenna at its top, and has a staircase with 1,665 steps. There are also elevators to take visitors to the top platform where there is a panoramic view of Paris. The original elevators, now computerized, are still in use. Over 60 tons of paint are applied to the tower every seven years to keep it from rusting.
The Eiffel Tower has become a symbol of Paris. It is the most recognized monument in Europe mainly because many people think it is an architectural masterpiece. Over 250 million people have visited it since May of 1889.
70.66. How long did it take to build The Eiffel Tower?(1 Point)A. around 2 years B. around 6 years C. 100 yearsD. 60 years
71.67. Who designed The Eiffel Tower? (1 Point)A. the Parisians B. the French RevolutionC. Gustave EiffelD. the World’s Fair
72.68. Why do they repaint The Eiffel Tower frequently?(1 Point)A. to keep it from rustingB. to make it more beautifulC. to attract visitorsD. to display it in the World’s Fair design competition
73.69. How many people have visited The Eiffel Tower until now?(1 Point)A. about 10.000 peopleB. about 324 million peopleC. more than 250 million peopleD. about 189 million people
74.70. What is the major reason for The Eiffel Tower to be a well-known tourist attraction in Europe?(1 Point)A. Because of its history.B. Because it is computerized.C. Because it has architectural beauty.D. Because it is repainted frequently.
24 tháng 3 2022

66: A

67:C

68:D

69:C

70:A

31 tháng 3 2022

n chất rắn =6,4 =0,1 mol

=>n Cu=n CuO=0,1 mol

Fe2O3+H2-to>Fe+H2O

CuO+H2-to>Cu+H2O

0,1----------------0,1

=>m CuO=0,1.80=8g

=>%m CuO=\(\dfrac{8}{40}100\)=20%

=>%m Fe2O3=100-20=80%

21 tháng 9 2023

Bài 1:

Ta có: \(n_{HCl}=0,2.0,5=0,1\left(mol\right)\)

BTNT H, có: \(n_{HCl}=2n_{H_2O}\Rightarrow n_{H_2O}=0,05\left(mol\right)\)

Theo ĐL BTKL, có: m oxit + mHCl = mmuối + mH2O

⇒ mmuối = 2,8 + 0,1.36,5 - 0,05.18 = 5,55 (g)

21 tháng 9 2023

Bài 2:

\(m_{KOH}=200.5,6\%=11,2\left(g\right)\Rightarrow n_{KOH}=\dfrac{11,2}{56}=0,2\left(mol\right)\)

PT: \(2KOH+CuCl_2\rightarrow2KCl+Cu\left(OH\right)_2\)

Theo PT: \(n_{Cu\left(OH\right)_2}=\dfrac{1}{2}n_{KOH}=0,1\left(mol\right)\)

\(\Rightarrow m_{Cu\left(OH\right)_2}=0,1.98=9,8\left(g\right)\)

16 tháng 3 2022

\(n_{XCl_3}=\dfrac{a}{M_X+106,5}\left(mol\right)\)

PTHH: 2X + 6HCl --> 2XCl3 + 3H2

=> \(n_X=\dfrac{a}{M_X+106,5}\left(mol\right)\)

\(n_{X_2\left(SO_4\right)_3}=\dfrac{b}{2.M_X+288}\left(mol\right)\)

PTHH: 2X + 3H2SO4 --> X2(SO4)3 + 3H2

=> \(n_X=\dfrac{b}{M_X+144}\left(mol\right)\)

31 tháng 3 2022

\(n_{H_2}=\dfrac{4,48}{22,4}=0,2\left(mol\right)\)

PTHH:

Fe + 2HCl ---> FeCl+ H2

2Al + 6HCl ---> 2AlCl3 + 3H2

Zn + 2HCl ---> ZnCl2 + H2

Theo các pthh trên: \(n_{HCl}=2n_{H_2}=2.0,2=0,4\left(mol\right)\)

\(\rightarrow\left\{{}\begin{matrix}m_{H_2}=0,2.2=0,4\left(g\right)\\m_{HCl}=0,4.36,5=14,6\left(g\right)\end{matrix}\right.\)

Áp dụng ĐLBTKL:

mKim loại + mHCl = mmuối khan + mH2

=> mMuối khan = 12 + 14,6 - 0,4 = 26,2 (g)

30 tháng 3 2022

pthh fe + 2hcl -> fecl2 + h2

 2al2 + 6hcl -> 2l2cl3 + 3h2

zn + 2hcl -> zncl2 + h2

11 tháng 4 2016

PTHH:

\(CuO+H_2\)  \(\underrightarrow{t^o}\)   \(Cu+H_2O\)           \(\left(1\right)\)
                  
\(Fe_2O_3+3H_2\)   \(\underrightarrow{t^o}\)   \(2Fe+3H_2O\)   \(\left(2\right)\)
          

Số mol H2 là 0,6 mol

Gọi số mol H2 tham gia pư 1 là x mol \(\left(0,6>x>0\right)\)

Số mol H2 tham gia pư 2 là \(\left(0,6-x\right)mol\)

Theo PTHH 1:

\(n_{CuO}=n_{H_2}=x\left(mol\right)\)

Theo PTHH 2:

\(n_{Fe_2O_3}=\frac{1}{3}n_{H_2}=\left(0,6-x\right):3\left(mol\right)\)

Theo bài khối lượng hh là 40g

Ta có pt: \(80x+\left(0,6-x\right)160:3=40\)

Giải pt ta được \(x=0,3\)

Vậy \(n_{CuO}=0,3\left(mol\right);n_{Fe_2O_3}=0,1\left(mol\right)\)

\(\%m_{CuO}=\left(0,3.80.100\right):40=60\%\)

\(\%m_{Fe_2O_3}=\left(0,1.160.100\right):40=40\%\)

11 tháng 4 2016

1)

PTHH:   \(2Cu+O_2\) \(\underrightarrow{t^o}\) \(2CuO\)

                x                              x

Gọi số mol Cu phản ứng là x mol ( x >0)

Chất rắn X gồm CuO và Cu

Ta có PT: 80x + 25,6 – 64x = 28,8

Giải PT ta được x = 0,2

Vậy khối lượng các chất trong X là:

\(m_{Cu}\) = 12,8 gam 

\(m_{CuO}\) = 16 gam

2)

Gọi kim loại hoá trị II là A.

PTHH:  \(A+2HCl\rightarrow ACl_2+H_2\)

Số mol \(H_2\)= 0,1 mol

Theo PTHH: \(n_A=n_{H_2}\)= 0,1 (mol)

Theo bài \(m_A\) = 2,4 gam   \(\Rightarrow\)        \(M_A\) = 2,4 : 0,1 = 24 gam

Vậy kim loại hoá trị II là Mg