Question

[Nguyễn Minh Khuê]

\(G=\left(\frac{1}{3}-1\right)\left(\frac{1}{6}-1\right)\left(\frac{1}{15}-1\right)\left(\frac{1}{21}-1\right)\left(\frac{1}{36}-1\right)\)

Tính G

Answer 1

[Minh Nguyen]

\(G=\left(\frac{1}{3}-1\right)\left(\frac{1}{6}-1\right)\left(\frac{1}{15}-1\right)\left(\frac{1}{21}-1\right)\left(\frac{1}{36}-1\right)\)

\(\Leftrightarrow G=-\frac{2}{3}.\frac{-5}{6}.\frac{-14}{15}.\frac{-20}{21}.\frac{-35}{36}\)

\(\Leftrightarrow G=\frac{-2.}{3}.\frac{5}{6}.\frac{14}{15}.\frac{20}{21}.\frac{35}{36}\)

\(\Leftrightarrow G=\frac{-2.5.2.7.2.2.5.5.7}{3.2.3.3.5.3.7.2.3.2.3}\)

\(\Leftrightarrow G=\frac{-2^4.5^3.7^2}{2^3.3^6.5.7}\)

\(\Leftrightarrow G=\frac{-2.5^2.7}{3^6}\)

\(\Leftrightarrow G=\frac{-350}{729}\)

P/s : Xin lỗi vì cách giải cùi bắp của mình :((