Câu hỏi của Hồng Nguyễn

Question

Giúp mình bài 19 với câu d bài trên Với ạ😭

Nguyễn Lê Phước Thịnh · Accepted Answer

Bài 19:a: $A=5x+\dfrac{1}{9}y=5\cdot\dfrac{-1}{10}+\dfrac{1}{9}\cdot4.8=\dfrac{-1}{2}+\dfrac{8}{15}=\dfrac{-15+16}{30}=\dfrac{1}{30}$b: $A=x-\dfrac{2}{3}=\dfrac{-1}{3}-\dfrac{2}{3}=-1$Câu trả lời: Bài 19:a: $A=5x+\dfrac{1}{9}y=5\cdot\dfrac{-1}{10}+\dfrac{1}{9}\cdot4.8=\dfrac{-1}{2}+\dfrac{8}{15}=\dfrac{-15+16}{30}=\dfrac{1}{30}$b: $A=x-\dfrac{2}{3}=\dfrac{-1}{3}-\dfrac{2}{3}=-1$

☆Châuuu~~~(๑╹ω╹๑ )☆ · Answer

$a,7x-2x-\dfrac{2}{3}y+\dfrac{7}{9}y=5x+\dfrac{1}{9}y\
=5.\left(\dfrac{-1}{10}\right)+\dfrac{1}{9}.4,8\
=\dfrac{-1}{2}+\dfrac{8}{15}=\dfrac{1}{30}\
b,x=\dfrac{0,2-0,375+\dfrac{5}{11}}{-0,3+\dfrac{9}{16}-\dfrac{15}{22}}\
=\dfrac{-1}{3}+\dfrac{\dfrac{-7}{40}+\dfrac{5}{11}}{\dfrac{21}{80}-\dfrac{15}{22}}\
=\dfrac{-1}{3}+\dfrac{\dfrac{123}{440}}{\dfrac{-369}{880}}=\dfrac{-1}{3}+\dfrac{-2}{3}=\dfrac{-3}{3}=\left(-1\right)$Câu trả lời: $a,7x-2x-\dfrac{2}{3}y+\dfrac{7}{9}y=5x+\dfrac{1}{9}y\
=5.\left(\dfrac{-1}{10}\right)+\dfrac{1}{9}.4,8\
=\dfrac{-1}{2}+\dfrac{8}{15}=\dfrac{1}{30}\
b,x=\dfrac{0,2-0,375+\dfrac{5}{11}}{-0,3+\dfrac{9}{16}-\dfrac{15}{22}}\
=\dfrac{-1}{3}+\dfrac{\dfrac{-7}{40}+\dfrac{5}{11}}{\dfrac{21}{80}-\dfrac{15}{22}}\
=\dfrac{-1}{3}+\dfrac{\dfrac{123}{440}}{\dfrac{-369}{880}}=\dfrac{-1}{3}+\dfrac{-2}{3}=\dfrac{-3}{3}=\left(-1\right)$

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