Question

[Ninh Thanh Tú Anh]

Giải phương trình

\(\left(x-1\right)^2-1+x^2=\left(1-x\right)\left(x+3\right)\)

\(\left(x^2-1\right)\left(x+2\right)\left(x-3\right)=\left(x-1\right)\left(x^2-4\right)\left(x+5\right)\)

\(x^4-4x^3+3x^2+4x-4=0\)

\(x^4-4x^3+12x-9=0\)

Answer 1

[Kiệt Nguyễn]

\(\left(x-1\right)^2-1+x^2=\left(1-x\right)\left(x+3\right)\)

\(\Leftrightarrow\left(x-1\right)^2+\left(x-1\right)\left(x+1\right)=\left(1-x\right)\left(x+3\right)\)

\(\Leftrightarrow2x\left(x-1\right)=\left(1-x\right)\left(x+3\right)\)

\(\Leftrightarrow2x\left(x-1\right)+\left(x-1\right)\left(x+3\right)=0\)

\(\Leftrightarrow\left(x-1\right)\left(3x+3\right)=0\)

\(\Rightarrow x=\pm1\)

Answer 2

[Ninh Thanh Tú Anh]

Giúp tớ mấy câu còn lại đi các cậu, tớ cần gấp lắm ạ ;;-;;