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a) 9/22 và 33/18 = 1/2 x 3/2 = 3/4
b) 12/35 : 36/25 = 12/35 X 25/36 = 1/7 x 5/3 = 5/21
c) 19/17 : 76/51 = 19/17 x 51/76 = 1/1 x 3/4 = 3/4
k mk nha
\(\frac{9}{22}\times\frac{33}{18}=\frac{9\times3\times11}{2\times11\times9\times2}\)\(=\frac{3}{4}\)
\(\frac{12}{35}:\frac{36}{25}=\frac{12}{35}\times\frac{25}{36}\)\(=\frac{12\times5\times5}{5\times7\times12\times3}=\)\(\frac{5}{21}\)
\(\frac{10}{17}:\frac{76}{51}=\frac{10}{17}\times\frac{51}{76}\)\(=\frac{10\times3\times17}{17\times76}\)\(=\frac{30}{76}=\frac{15}{38}\)
a,\(\frac{3}{4}\)
b,\(\frac{5}{21}\)
c,\(\frac{15}{38}\)
a) 9/22 x 33/18 =3/4
b) 12/35 : 36/25 = 5/21
c) 19/17 : 76/51 =3/4
a) \(\frac{9}{22}\times\frac{33}{18}\)
\(=\frac{9}{22}\times\frac{11}{6}\)
\(=\frac{9\times11}{22\times6}=\frac{3}{4}\)
b) \(\frac{12}{35}:\frac{36}{25}=\frac{12}{35}\times\frac{25}{36}\)
\(=\frac{5}{21}\)
c) \(\frac{19}{17}:\frac{76}{51}=\frac{19}{17}\times\frac{51}{76}\)
\(=\frac{3}{4}\)
\(\frac{5}{9}\times\frac{12}{7}=\frac{5\times12}{9\times7}=\frac{5\times4\times3}{3\times3\times7}=\frac{20}{21}\)
\(\frac{6}{5}:\frac{8}{3}=\frac{6}{5}\times\frac{8}{3}=\frac{2\times3\times8}{5\times3}=\frac{16}{5}\)
\(\frac{9}{20}\times\frac{5}{12}=\frac{3\times3\times5}{4\times5\times4\times3}=\frac{3}{16}\)
\(\frac{15}{16}:\frac{25}{24}=\frac{15}{16}\times\frac{24}{25}=\frac{3\times5\times4\times2\times3}{4\times2\times2\times5\times5}=\frac{9}{10}\)
\(14\times\frac{5}{21}=\frac{2\times7\times5}{3\times7}=\frac{10}{3}\)
\(10:\frac{5}{3}=10\times\frac{3}{5}=\frac{2\times5\times3}{5}=6\)
\(\frac{5}{3}:10=\frac{5}{3}\times\frac{1}{10}=\frac{5}{3\times2\times5}=\frac{1}{6}\)
a) \(\frac{9}{22}.\frac{33}{18}=\frac{9.33}{22.18}=\frac{297}{396}=\frac{3}{4}\)
b) \(\frac{12}{35}:\frac{36}{25}=\frac{12}{35}.\frac{25}{36}=\frac{12.25}{35.36}=\frac{300}{1260}=\frac{5}{21}\)
c) \(\frac{19}{17}:\frac{76}{51}=\frac{19}{17}.\frac{51}{76}=\frac{19.51}{17.76}=\frac{969}{1292}=\frac{3}{4}\)
2*32*12*4*6*41= ( 2 * 12) * (32*41) * (4*6)
= 24 * 1312 * 24
= 24 *24 * 1312
= 576 * 1312
= 755712
2*33*7+7*2*45+7*22*2 = 7 * ( 2*33+ 2*45 + 22*2)
= 7 * ( 66+90+44)
= 7* 200 = 1400
17*85+15*17-120 = 17 * ( 85 + 15) - 120
= 17*100- 120
=1700-120
= 1580
a) x4+x3+2x2+x+1=(x4+x3+x2)+(x2+x+1)=x2(x2+x+1)+(x2+x+1)=(x2+x+1)(x2+1)
b)a3+b3+c3-3abc=a3+3ab(a+b)+b3+c3 -(3ab(a+b)+3abc)=(a+b)3+c3-3ab(a+b+c)
=(a+b+c)((a+b)2-(a+b)c+c2)-3ab(a+b+c)=(a+b+c)(a2+2ab+b2-ac-ab+c2-3ab)=(a+b+c)(a2+b2+c2-ab-ac-bc)
c)Đặt x-y=a;y-z=b;z-x=c
a+b+c=x-y-z+z-x=o
đưa về như bài b
d)nhóm 2 hạng tử đầu lại và 2hangj tử sau lại để 2 hạng tử sau ở trong ngoặc sau đó áp dụng hằng đẳng thức dề tính sau đó dặt nhân tử chung
e)x2(y-z)+y2(z-x)+z2(x-y)=x2(y-z)-y2((y-z)+(x-y))+z2(x-y)
=x2(y-z)-y2(y-z)-y2(x-y)+z2(x-y)=(y-z)(x2-y2)-(x-y)(y2-z2)=(y-z)(x2-2y2+xy+xz+yz)