Question

[Nguyễn Duy Khang]

Giải các bất phương trình sau 

a) (x-4)²<x(x-8)

b) x+\(\dfrac{1}{2}\)\(\overset{>}{-}\)\(\dfrac{3-5x}{-3}\)

c) \(\dfrac{x-7}{-4}\)\(\overset{< }{-}\)\(\dfrac{4-2x}{-3}\)

Answer 1

[Nguyễn Lê Phước Thịnh]

a: =>x^2-8x+16<x^2-8x

=>16<0(loại)

b: =>\(x+\dfrac{1}{2}>=\dfrac{5x-3}{3}\)

=>x+1/2>=5/3x-1

=>-2/3x>=-3/2

=>x<=3/2:2/3=9/4

c: =>\(\dfrac{7-x}{4}< =\dfrac{2x-4}{3}\)

=>21-3x<=8x-16

=>-11x<=-37

=>x>=37/11