Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a,\(8x^2-8xy+2x=2x\left(4x-8y+1\right)\)
b,\(\left(x^2+2x\right)\left(x^2+4x+3\right)-24=x\left(x+2\right)\left(x+1\right)\left(x+3\right)-24\)
\(=\left(x^2+3x\right)\left(x^2+3x+2\right)-24=\left(t+1\right)\left(t-1\right)-24=t^2-5^2=\left(t+5\right)\left(t-5\right)\)
\(=\left(x^2+3x+6\right)\left(x^2+3x-4\right)\)( đặt t = x2 + 3x + 1 )
Bài 2:
a) =a2b - a2c + b2c - ab2 + ac2 - bc2
=(a2b - bc2) - (a2c - ac2) + (b2c - ab2)
=b(a-c)(a+c) - ac(a-c) - b2(a-c)
=(a - c)(ab -bc - ac - b2)
b)=(1 - 2a + a2) - (b2 - 2bc + c2)
=(1 - a)2 - (b - c)2
=(c - b - a + 1)(b - c - a + 1)
1)
b) \(\left(x-z\right)^2-y^2+2y-1\)
\(=\left(x^2-2xz+z^2\right)-\left(y-1\right)^2\)
\(=\left(y-z\right)^2-\left(y-1\right)^2\)
\(=\left[\left(x-z\right)+\left(y-1\right)\right]\cdot\left[\left(x-z\right)-\left(y+1\right)\right]\)
\(=\left(x-z+y-1\right)\cdot\left(x-z-y-1\right)\)
a ) \(a^2\left(b-c\right)+b^2\left(c-a\right)+c^2\left(a-b\right)\)
\(=a^2b-a^2c+b^2c-ab^2+ac^2-bc^2\)
\(=\left(a^2b-bc^2\right)-\left(a^2c-ac^2\right)+\left(b^2c-ab^2\right)\)
\(=b\left(a-c\right)\left(a+c\right)-ac\left(a-c\right)-b^2\left(a-c\right)\)
\(=\left(a-c\right)\left(ab-bc-ac-b^2\right)\)
\(1-2a+2bc+a^2-b^2-c^2\)
\(=\left(1-2a+a^2\right)-\left(b^2-2bc+c^2\right)\)
\(=\left(1-a\right)^2-\left(b-c\right)^2\)
\(=\left(c-b-a+1\right)\left(b-c-a+1\right)\)