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a) (–2) + (–5) = – (2 + 5) = –7.
So sánh –7 và –5 có: Vì |–7| = 7; |–5| = 5, mà 7 > 5 nên (–7) < (–5).
Vậy (–2) + (–5) < (–5).
b) (–3) + (–8) = – (3 + 8) = –11.
So sánh –10 và –11: Vì |–10| = 10; |–11| = 11; mà 10 < 11 nên (–10) > (–11).
Vậy (–10) > (–3) + (–8) .
\(12000-\left(1500\cdot2+1800\cdot3+1800\cdot2:3\right)\)
\(=12000-\left(3000+5400+1200\right)\)
\(=12000-9600\)
\(=2400\)
\(\left(0+1\right)^2=0^2+1^2\)
\(\left(1+2\right)^2>1^2+2^2\)
\(\left(2+3\right)^2>2^2+3^2\)
\(a,3\cdot5^{2 }-16:2^2=3\cdot25-16:4=75-4=71\)
\(b,2^3\cdot17-2^3\cdot14=2^3\cdot\left(17-14\right)=8\cdot3=24\)
\(c,15,141+59\cdot15=15,141+885=900,141\)
\(d,17\cdot85+15\cdot17-120=17\cdot\left(85+15\right)-120=17\cdot100-120=1700-120=1580\)
\(e,20-\left(30-\left(5-1\right)^2\right)=20-\left(30-\left(4\right)^2\right)=20-\left(30-16\right)=20-14=6\)
\(a,70-5\cdot\left(x-3\right)=45\)
\(< =>5\cdot\left(x-3\right)=70-45=25\)
\(< =>x-3=25:5=5\)
\(< =>x=5+3=8\)
\(b,10+2\cdot x=4^5:4^3\)
\(< =>10+2\cdot x=4^2=16\)
\(< =>2\cdot x=16-10=6\)
\(< =>x=6:2=3\)
CHUC BAN HOC TOT :))
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