Question

[Cậu Vàng]

\(\dfrac{120}{x}\) + \(\dfrac{120}{x-10}\) =\(\dfrac{3}{5}\)
Giải phương trình

Answer 1

[YangSu]

\(\dfrac{120}{x}+\dfrac{120}{x-10}=\dfrac{3}{5}\left(dkxd:x>0,x\ne10\right)\)

\(\Leftrightarrow\dfrac{120}{x}+\dfrac{120}{x-10}-\dfrac{3}{5}=0\)

\(\Leftrightarrow\dfrac{120.5\left(x-10\right)+5.120x-3x\left(x-10\right)}{5x\left(x-10\right)}=0\)

\(\Leftrightarrow600x-6000+600x-3x^2+30x=0\)

\(\Leftrightarrow-3x^2+1230x-6000=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}x\approx405\\x\approx5\end{matrix}\right.\)\(\left(tmdk\right)\)

Vậy ...

Answer 2

[Kiều Vũ Linh]

ĐKXĐ: x ≠ 0; x ≠ 10 em ơi