Question

[Nguyen Thi Yen Anh]

cho x+y=101. Tính giá trị biểu thức:

x^3-3.x^2+3.x^2.y+3.x.y^2+y^3-3.y^2-6.x.y+3.x+3.y+2012

Answer 1

[Sắc màu]

= ( x³ + 3x²y + 3xy² + y³ ) - 6xy - 3x² - 3y² + 3x + 3y + 2012

= ( x + y )³ - 3xy - 3x² - 3xy - y² + 3. ( x + y ) + 2012

= ( x + y )³ - 3x ( x + y ) - 3y .( x + y ) + 3.( x + y ) + 2012

= ( x + y )³ - 3.( x + y ) ( x + y ) + 3( x + y ) + 2012

= 101³ - 3.101² + 3.101 + 2012

= 1002013