Question

[le diep]

cho x,y thỏa mãn :\(\left(\sqrt{x^2+3}+x\right)\cdot\left(\sqrt{y^2+3}+y\right)=3\)

tính A=\(x^{2013}+y^{2013}+1\)

Answer 1

[Tuyển Trần Thị]

\(\)\(\left(\sqrt{x^2+3}+x\right)\left(\sqrt{x^2+3}-x\right)=3=\left(\sqrt{x^2+3}+x\right)\left(\sqrt{y^2+3}+y\right)\)

\(\Rightarrow\sqrt{x^2+3}-x=\sqrt{y^2+3}+y\)(1)

ttu \(\sqrt{y^2+3}-y=\sqrt{x^2+3}+x\) (2)

lay (1)+(2)

\(-\left(x+y\right)=x+y\Rightarrow x+y=0\)

ma \(A=x^{2013}+y^{2013}+1=\left(x+y\right)M+1=1\)

Answer 2

[le diep]

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