Question

[Phạm Thúy Hường]

Cho \(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}=2\) và a+b+c=abc. Chứng minh rằng: \(\frac{1}{a^2}+\frac{1}{b^2}+\frac{1}{c^2}=2\)

Answer 1

[Nguyễn Lê Phước Thịnh]

\(\left(\dfrac{1}{a}+\dfrac{1}{b}+\dfrac{1}{c}\right)^2=4\)

\(\Leftrightarrow\dfrac{1}{a^2}+\dfrac{1}{b^2}+\dfrac{1}{c^2}+2\left(\dfrac{1}{ab}+\dfrac{1}{bc}+\dfrac{1}{ac}\right)=4\)

\(\Leftrightarrow\dfrac{1}{a^2}+\dfrac{1}{b^2}+\dfrac{1}{c^2}=2\)