Question

[Đẹp Trai Không Bao Giờ Sai]

Cho a, b, c > 0 thỏa mãn a + b = 2c. CMR \(\frac{1}{\sqrt{a}+\sqrt{c}}+\frac{1}{\sqrt{b}+\sqrt{c}}=\frac{2}{\sqrt{a}+\sqrt{b}}\)

Answer 1

[Trần Quang Hưng]

Qui đồng chứng minh tương đương là ra

Answer 2

[Nguyễn Việt Lâm]

\(a+b=2c\Rightarrow\left\{{}\begin{matrix}c=\frac{a+b}{2}\\a-c=c-b\end{matrix}\right.\)

\(\frac{1}{\sqrt{a}+\sqrt{c}}+\frac{1}{\sqrt{b}+\sqrt{c}}=\frac{\sqrt{a}-\sqrt{c}}{a-c}+\frac{\sqrt{b}-\sqrt{c}}{b-c}=\frac{\sqrt{a}-\sqrt{c}}{a-c}-\frac{\sqrt{b}-\sqrt{c}}{a-c}\)

\(=\frac{\sqrt{a}-\sqrt{b}}{a-c}=\frac{\sqrt{a}-\sqrt{b}}{a-\frac{a+b}{2}}=\frac{2\left(\sqrt{a}-\sqrt{b}\right)}{a-b}=\frac{2}{\sqrt{a}+\sqrt{b}}\)