Question

[Nấm Chanel]

Bài 2: ( chỉ ghi kết quả )

a) Tìm x biết : \(\dfrac{1}{2-\dfrac{3}{4+\dfrac{5}{6-\dfrac{7}{8+\dfrac{9}{10}}}}}=\dfrac{1}{x+\dfrac{1}{3+\dfrac{1}{5}}}+\dfrac{1}{1+\dfrac{1}{1+\dfrac{1}{2}}}\)

b) Tính: ( kết quả lấy 4 chữ số thập phân)

\(P=\dfrac{\sin^390^0-\cot^330^0-\cos^245^0+\tan20^0}{2\sqrt{7}+\sin108^0\cos32^0\tan64^0}\)

Answer 1

[๖ۣۜĐặng♥๖ۣۜQuý]

\(\dfrac{1}{2-\dfrac{3}{4+\dfrac{5}{6-\dfrac{7}{8+\dfrac{9}{10}}}}}=\dfrac{1}{x+\dfrac{1}{3+\dfrac{1}{5}}}+\dfrac{1}{1+\dfrac{1}{1+\dfrac{1}{2}}}\\ \Leftrightarrow\dfrac{767}{1070}=\dfrac{1}{x+\dfrac{5}{16}}+\dfrac{3}{5}\\ \Leftrightarrow\dfrac{25}{214}=\dfrac{1}{x+\dfrac{5}{16}}\\ \Rightarrow x+\dfrac{5}{16}=\dfrac{214}{25}\Rightarrow x=\dfrac{3299}{400}\)