Question

[Đức Anh Noo Nguyen]

Bài 1:Phân tích đa thức thành nhân tử:

1)3x²-6x+9x²

^{2)10x(x-y)-6y(y-x)}

3)3x²+5y-3xy -5x

4)3y²-3z²+3x²+6xy

5)16x³+54y³

6)x²-25-2xy+y²

⁷⁾x⁵-3x⁴⁺3x³-x²

8)

Answer 1

[B.Thị Anh Thơ]

a,3x²-6x+9x²

=>12x²-6x

=>6x(2x-1)

b,10x(x-y)-6y(y-x)

=>10x(x-y)-6y(-(x-y))

=>10x(x-y)+6y(x-y)

=>2(x-y)(5x+3y)

c,3x²+5y-3xy-5x

=>3x(x-y)-5(x-y)

=>(x-y)(3x-5)

d,3y²-3z²+3x²+6xy

=>3(y²-z²+x²+2xy)

=>3[(y+x)²-z²]

=>3(y+x-z)(y+x+z)

e,16x³+54y³

=>2(8x³+27y³)

=>2(2x+3y)(4x²-6xy+9y²)

g,x²-25-2xy+y²

=>(x-y)²-25

=>(x-y-5)(x-y+5)

h,x⁵-3x⁴+3x³-x²

=>x²(x³-3x²+3x-1)

=>x²(x-1)³

Nhớ tick cho mk nhé

Answer 2

[Trieu Mai]