Question

[nguyễn khuyến]

  Bài 1 : Tìm x,y thuộc Z :

1,( x + 1 ) . ( y - 2 ) = 0

2,( x - 5 ) . ( y - 7 ) = 1

3,( x + 4 ) . ( y - 2 ) = 2

4,( x - 4 ) . ( y + 3 ) = -3

5,( x + 3 ) . ( y - 6 ) = -4

6,( x - 8 ) . ( y + 7 ) = 5

7,( x + 7 ) . ( y - 3 ) = -6

8,( x - 6 ) . ( y + 2 ) = 7

Answer 1

[Hà Nhật Minh]

1)\(\left(x+1\right).\left(y-2\right)=0\)                                       \(\left(x,y\inℤ\right)\)

\(\Rightarrow\orbr{\begin{cases}x+1=0\\y-2=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=-1\\y=2\end{cases}}\)

2)\(\left(x-5\right).\left(y-7\right)=1\)

x-5	1	-1
y-7	1	-1
x	6	4
y	8	6

3)\(\left(x+4\right).\left(y-2\right)=2\)

x+4	1	2	-1	-2
y-2	2	1	-2	-1
x	-3	-2	-5	-6
y	4	3	0	1

4)\(\left(x-4\right).\left(y+3\right)=-3\)

x-4	1	-1	3	-3
y+3	-3	3	-1	1
x	5	3	7	1
y	-6	0	-4	-2

5)\(\left(x+3\right).\left(y-6\right)=-4\)

x+3	-1	1	-4	4	2	-2
y-6	4	-4	1	-1	-2	2
x	-4	-2	-7	1	-1	-5
y	10	2	7	5	4	8

6)\(\left(x-8\right).\left(y+7\right)=5\)

x-8	1	5	-1	-5
y+7	5	1	-5	-1
x	9	13	7	3
y	-2	-6	-12	-8

7)\(\left(x+7\right).\left(y-3\right)=-6\)

x+7	-1	1	-6	6	-2	2	-3	3
y-3	6	-6	1	-1	3	-3	2	-2
x	-8	-6	-13	-1	-9	-5	-10	-4
y	9	-3	4	2	6	0	5	1

8)\(\left(x-6\right).\left(y+2\right)=7\)

x-6	1	7	-1	-7
y+2	7	1	-7	-1
x	7	13	5	-1
y	5	-1	-9	-3

ok :)