Question

[bella nguyen]

Bài 1 : làm tính chia

a, ( 6x^2 + 13x - 5x ) : 2x + 5

b, ( 12x^2 - 14x + 3 - 6x^3 + x^4) : (1- 4x + x^2)

c, ( 2x^2 - 5x^3 + 2x + 2x^4 -1 ):( x^2 - 2x-1)

d, ( x^2 + 2xy + y^2 ) : x +y

Answer 1

[Nguyễn Lê Phước Thịnh]

a: \(=\dfrac{6x^3+13x^2-5x}{2x+5}=\dfrac{6x^3+15x^2-2x^2-5x}{2x+5}=3x^2-x\)

b: \(=\dfrac{x^4-6x^3+12x^2-14x+3}{x^2-4x+1}\)

\(=\dfrac{x^4-4x^3+x^2-2x^3+8x^2-2x+3x^2-12x+3}{x^2-4x+1}\)

\(=x^2-2x+3\)

d: \(=\dfrac{\left(x+y\right)^2}{x+y}=x+y\)