Question

[Trịnh Thị Thảo Nhi]

A=\(\dfrac{2^{19}\times27^3-15\times\left(-4\right)^9\times9^4}{6^9\times2^{10}+\left(-12\right)^{10}}\)

Answer 1

[Nguyễn Lê Phước Thịnh]

\(A=\dfrac{2^{19}\cdot3^9-3\cdot5\cdot2^{18}\cdot3^8}{2^9\cdot2^{10}\cdot3^9+2^{20}\cdot3^{10}}\)

\(=\dfrac{2^{19}\cdot3^9-2^{18}\cdot3^9\cdot5}{2^{19}\cdot3^9+2^{20}\cdot3^{10}}\)

\(=\dfrac{2^{18}\cdot3^9\left(2-5\right)}{2^{19}\cdot3^9\cdot7}=\dfrac{1}{2}\cdot\dfrac{-3}{7}=\dfrac{-3}{14}\)