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`#3107`
a)
`8x^2 - 5 = 67 `
`=> 8x^2 = 67 + 5`
`=> 8x^2 = 72`
`=> x^2 = 9`
`=> x^2 = (+-3)^2`
`=> x = +-3`
Vậy, `x \in {-3;3}`
b)
`(4x - 2)^4=16`
`=> (4x - 2) = (+-2)^4`
`=> ` TH1: `4x - 2 = 2`
`=> 4x = 4`
`=> x =1`
TH2: `4x - 2 = -2`
`=> 4x = 0`
`=> x=0`
Vậy, `x \in {0; 1}.`
a) \(8x^2-5=67\)
\(8x^2=72\)
\(x^2=9\)
\(x=3\)
Vậy x = 3
b) \(\left(4x-2\right)^4=16\)
\(\left(4x-2\right)^2=4\)
\(4x-2=2\)
\(4x=4\)
\(x=1\)
Vậy x = 1
2: 12-10x=25-30x
=>20x=13
=>x=13/20
3: \(3\left(2x+3\right)-2\left(4x-5\right)=10x+21\)
=>6x+9-8x+10=10x+21
=>10x+21=-2x+19
=>12x=-2
=>x=-1/6
4: \(\Leftrightarrow25x-15-6x+12=11-5x\)
=>19x-3=11-5x
=>24x=14
=>x=7/12
5: \(\Leftrightarrow8-12x-5+10x=4-6x\)
=>4-6x=-2x+3
=>-4x=-1
=>x=1/4
6: \(\Leftrightarrow32x-24-6+9x=13-40x\)
=>41x-30=13-40x
=>81x=43
=>x=43/81
7: \(\Leftrightarrow10x-5+20x=5x-11\)
=>30x-5=5x-11
=>25x=-6
=>x=-6/25
\(a)5\left(3-2x\right)+5\left(x-4\right)=6-4x\)
\(\Leftrightarrow5\left(3-2x+x-4\right)=6-4x\)
\(\Leftrightarrow5\left(-x-1\right)=6-4x\)
\(\Leftrightarrow-5x-5=6-4x\)
\(\Leftrightarrow-x=11\Leftrightarrow x=-11\)
Vậy \(x=-11\)
1.
12 - 10x = 25 - 30x
<=> 12 - 25 = -30x + 10x
<=> - 20x = -13
<=> x = 13/20
2.
3(2x+3) - 2(4x - 5) = 10x+21
<=> 6x + 9 - (8x - 10) = 10x + 21
<=> 6x + 9 - 8x + 10 = 10x + 21
<=> -2x + 19 = 10x + 21
<=> -12x = 2
<=> x = -1/6
1: =>-10x+30x=25-12
=>20x=13
=>x=13/20
2: =>6x+9-8x+10=10x+21
=>10x+21=-2x+19
=>12x=-2
=>x=-1/6
a, thiếu đề
b, -5 ( 2 - x ) + 4 ( x - 3 ) = 10x - 15
<=> -10 + 5x + 4x - 12 = 10x - 15
<=> -x = 7 <=> x = 7
c,-7(5-x)-2(x-10)=15
<=> -35 + 7x - 2x + 20 = 15 <=> 5x = 30 <=> x = 6
d, -4(x+1) + 89x - 3 = 24
<=> 85x = 31 <=> x = 31/85
e, 5(x-30-2(x+6)) = 9
<=> 5 (-x-49) = 9 <=> -5x = 254 <=> x = -254/5
b: =>-10+5x+4x-12=10x-15
=>9x-10x=-15+22
=>-x=7
hay x=-7
c: =>-35+7x-2x+20=15
=>5x-15=15
=>x=6
d: =>-4x-4+72x-24=24
=>68x-32=24
hay x=14/17
\(\left(2x+3\right)\cdot\left(10x+2\right)=\left(5x+2\right)\cdot\left(4x+5\right)\)
\(\Leftrightarrow20x^2+4x+30x+6-20x^2-25x-8x-10=0\)
\(\Leftrightarrow x-4=0\)
\(\Leftrightarrow x=4\)
\(< =>20x^2+4x+30x+6=20x^2+25x+8x+10\)
\(< =>34x+6-25x-8x-10=0\)
\(< =>x-4=0< =>x=4\)
\(8x^2-2x-3=\left(x-\frac{3}{4}\right)\left(x+\frac{1}{2}\right)\)
\(8x^2+10x-3=\left(x-\frac{1}{4}\right)\left(x+\frac{3}{2}\right)\)
\(10x^2-4x-6=\left(x-1\right)\left(x+\frac{3}{5}\right)\)
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