72x+72x+3=344 (5-x)(9x2-4)=0 \(\left|2-2x\right|\)-3,75=(-0,5)2 \(\sqrt{x-1}\)+\(\dfrac{2}{3}\)=1 (\(\dfrac{1}{3}\)-\(\dfrac{3}{2}\)x)2=2\(\dfrac{1}{4}\) giúp...

(5 - \(x\))(9\(x^2\) - 4) =0 \(\left[{}\begin{matrix}5-x=0\\9x^2-4=0\end{matrix}\right.\) \(\left[{}\begin{matrix}x=5\\9x^2=4\end{matrix}\right.\) \(\left[{}\begin{matrix}x=5\\x^2=\dfrac{4}{9}\end{matrix}\right.\) \(\left[{}\begin{matrix}x=5\\x=-\dfrac{2}{3}\\x=\dfrac{2}{3}\end{matrix}\right.\) Vậy \(x\) \(\in\) { - \(\dfrac{2}{3}\); \(\dfrac{2}{3}\); \(5\)} Câu trả lời: (5 - \(x\))(9\(x^2\) - 4) =0 \(\left[{}\begin{matrix}5-x=0\\9x^2-4=0\end{matrix}\right.\) \(\left[{}\begin{matrix}x=5\\9x^2=4\end{matrix}\right.\) \(\left[{}\begin{matrix}x=5\\x^2=\dfrac{4}{9}\end{matrix}\right.\) \(\left[{}\begin{matrix}x=5\\x=-\dfrac{2}{3}\\x=\dfrac{2}{3}\end{matrix}\right.\) Vậy \(x\) \(\in\) { - \(\dfrac{2}{3}\); \(\dfrac{2}{3}\); \(5\)}

72\(x\) + 72\(x\) + 3 = 344 72\(x\) \(\times\) ( 1 + 73) = 344 72\(x\) \(\times\) (1 + 343) = 344 72\(x\) \(\times\) 344 = 344 72\(x\) = 344 : 344 72\(x\) = 1 72\(x\) = 70 \(2x\) = 0 \(x\) = 0 Kết luận: \(x\) = 0Câu trả lời: 72\(x\) + 72\(x\) + 3 = 344 72\(x\) \(\times\) ( 1 + 73) = 344 72\(x\) \(\times\) (1 + 343) = 344 72\(x\) \(\times\) 344 = 344 72\(x\) = 344 : 344 72\(x\) = 1 72\(x\) = 70 \(2x\) = 0 \(x\) = 0 Kết luận: \(x\) = 0