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1) 42/35 - [ 33/14 . 21/22 - ( 54/25 : 27/25 - 7/10 )]
= 42/35 - ( 9/4-13/10)
=42/35-19/20
=1/4
2) a) 5/21 . x/34 = 35/102
x/34=35/102 : 5/21
x/34=49/34
=> x=34
Vậy x=34
b) 15/x . 21/13 = 45/91
15/x=45/91 : 21/13
15/x=15/49
=> x=49
Vậy x=49
a: AB=OA+OB=m+5
b: Vì OB<OC
nên B nằm giữa O và C
c: B là trung điểm của OC
=>OB=BC
=>m=6/2=3cm
a)-4/11+5/6+7/11-5/6
b)-5/6.7/13+19/13.6/-5+2/5
c)3/7.(-0,5+3/2)-2/7:25%
mọi người giúp e vs ạ
e cần gấp
a; - \(\dfrac{4}{11}\) + \(\dfrac{5}{6}\) + \(\dfrac{7}{11}\) - \(\dfrac{5}{6}\)
= (-\(\dfrac{4}{11}\) + \(\dfrac{7}{11}\)) + (\(\dfrac{5}{6}\) - \(\dfrac{5}{6}\))
= - \(\dfrac{3}{11}\) + 0
= - \(\dfrac{3}{11}\)
b; -\(\dfrac{5}{6}\).\(\dfrac{7}{13}\) + \(\dfrac{19}{13}\).\(\dfrac{6}{-5}\) + \(\dfrac{2}{5}\)
= - \(\dfrac{35}{78}\) - \(\dfrac{114}{65}\) + \(\dfrac{2}{5}\)
= - \(\dfrac{859}{390}\) + \(\dfrac{2}{5}\)
= - \(\dfrac{703}{390}\)
A=\(\frac{6}{19}\). \(\frac{-7}{11}\)+\(\frac{6}{19}\).\(\frac{-4}{11}\)+\(\frac{-13}{19}\)
=\(\frac{6}{19}\).(\(\frac{-7}{11}\)+\(\frac{-4}{11}\))+\(\frac{-13}{19}\)
=\(\frac{6}{19}\).\(\frac{-11}{11}\)+\(\frac{-13}{19}\)
=\(\frac{6}{19}\).-1 +\(\frac{-13}{19}\)
=\(\frac{-6}{19}\)+\(\frac{-13}{19}\)
=\(\frac{-19}{19}\)
+1
\(-\dfrac{5}{6}\cdot\dfrac{7}{13}+\dfrac{19}{13}:\dfrac{6}{-5}+\dfrac{2}{5}\)
\(=-\dfrac{5}{6}\cdot\dfrac{7}{13}+\dfrac{19}{13}\cdot-\dfrac{5}{6}+\dfrac{2}{5}\)
\(=-\dfrac{5}{6}\left(\dfrac{7}{13}+\dfrac{9}{13}\right)+\dfrac{2}{5}\)
\(=-\dfrac{5}{6}\cdot2+\dfrac{2}{5}\)
\(=-\dfrac{5}{3}+\dfrac{2}{5}\)
\(=-\dfrac{25}{15}+\dfrac{6}{15}\)
\(=-\dfrac{19}{15}\)
#データネ
xem lại nha
( -25 + 6 = 31?) =))