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25 . 5 . 4 . 27 . 2
= ( 25 . 4 ) . ( 5 . 2 ) . 27
= 100 . 10 . 27
= 1000 . 27
= 27 000
a) \(...=-\dfrac{12}{46}-\dfrac{15}{21}+\dfrac{3}{7}-\dfrac{7}{23}\)
\(=-\dfrac{12}{46}-\dfrac{7}{23}-\dfrac{15}{21}+\dfrac{3}{7}\)
\(=-\dfrac{6}{23}-\dfrac{7}{23}-\dfrac{5}{7}+\dfrac{3}{7}\)
\(=-\dfrac{13}{23}-\dfrac{2}{7}\)
\(=-\dfrac{13.7}{23.7}-\dfrac{2.23}{23.7}\)
\(=-\dfrac{91}{161}-\dfrac{46}{161}=-\dfrac{137}{161}\)
b) \(...=-21+\dfrac{7}{9}-\dfrac{3}{17}+\dfrac{25}{9}\)
\(=-21-\dfrac{3}{17}+\dfrac{7}{9}+\dfrac{25}{9}\)
\(=-21-\dfrac{3}{17}+\dfrac{32}{9}\)
\(=-\dfrac{3213}{153}-\dfrac{27}{153}+\dfrac{544}{153}=-\dfrac{2696}{153}\)
a) \(198+789+502+311\)
\(=\left(198+502\right)+\left(789+311\right)\)
\(=700+1100\)
\(=1800\)
b) \(15.6.4.125.8\)
\(=\left(15.4\right).6.\left(125.8\right)\)
\(=60.6.1000\)
\(=360000\)
c) \(367+129+133+371+17\)
\(=\left(367+133\right)+\left(129+371\right)+17\)
\(=500+500+17\)
\(=1000+17\)
\(=1017\)
d) \(37.64+37.35+37\)
\(=37.\left(64+35+1\right)\)
\(=37.100\)
\(=3700\)
e) \(3.25.8+4.37.6+2.38.12\)
\(=\left(3.8\right).25+\left(4.6\right).37+\left(2.12\right).38\)
\(=24.25+24.37+24.38\)
\(=24.\left(25+37+38\right)\)
\(=24.100\)
\(=2400\)
f) \(136.48+16.272+68.20.2\)
\(=136.48+16.2.136+68.2.20\)
\(=136.48+32.136+136.20\)
\(=136.\left(48+32+20\right)\)
\(=136.100\)
\(=13600\)
g) \(1+6+11+16+...+46+51\)
Số số hạng là :
\(\left(51-1\right):5+1=11\) ( số )
Tổng là :
\(\left(1+51\right)\times11:2=286\)
Chúc bạn học tốt
15 . 100 + 25 . 100 + 60 . 100
= (15 + 25 + 60) . 100
= 100 . 100
= 10000
15 . 100 + 25 . 100 + 60 . 100
= ( 15 + 25 + 60 ) . 100
= 100 . 100
= 10 000
1 + 2 + 3 + ...........+x = 45
(x + 1){( x-1) :1 +1) :2 = 45
(x+1)x = 90 = 9 x10
x = 9
Câu 9: Tính bằng cách thuận tiện nhất:
a) 876 × 64 – 876 × 54 |
=>876x(64-54)=876x10=8760
b) 37 × 25 + 37 × 35 + 37 × 39 + 37
37x(25+35+39)=37x99=3663
Chúc em học tốt
\(=25\cdot555+25\cdot1505=51500\)
25.(215 + 170) + 170.25 + 215.175
= 25. 555 + 25. 1505
= 13875 + 37625
= 51500