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a. \(\frac{26}{5-2\sqrt{3}}\)=\(\frac{26\cdot\left(5+2\sqrt{3}\right)}{\left(5-2\sqrt{3}\right)\left(5+2\sqrt{3}\right)}\)=\(\frac{26\cdot\left(5+2\sqrt{3}\right)}{5^2-\left(2\sqrt{3}\right)^2}=\frac{26\cdot\left(5+2\sqrt{3}\right)}{13}=2\cdot\left(5+2\sqrt{3}\right)=10+4\sqrt{3}\)
b.\(\frac{9-2\sqrt{3}}{3\sqrt{6}-2\sqrt{2}}=\frac{\sqrt{3}\cdot\left(3\sqrt{3}-2\right)}{\sqrt{2}\cdot\left(3\sqrt{3}-2\right)}=\frac{\sqrt{3}}{\sqrt{2}}=\frac{\sqrt{6}}{2}\)
c.\(\frac{2\sqrt{10}-5}{4-\sqrt{10}}=\frac{\sqrt{5}\cdot\left(2\sqrt{2}-\sqrt{5}\right)}{\sqrt{2}\cdot\left(2\sqrt{2}-\sqrt{5}\right)}=\frac{\sqrt{5}}{\sqrt{2}}=\frac{\sqrt{10}}{2}\)
d.\(2\sqrt{5}-\sqrt{125}-\sqrt{80}+\sqrt{605}=2\sqrt{5}-5\sqrt{5}-4\sqrt{5}+11\sqrt{5}\)=\(4\sqrt{5}\)
\(a,\frac{2\sqrt{10}-5}{4-\sqrt{10}}=\frac{\left(2\sqrt{10}-5\right)\left(4+\sqrt{10}\right)}{\left(4-\sqrt{10}\right)\left(4+\sqrt{10}\right)}=\frac{20+6\sqrt{10}-5\sqrt{10}-9}{16-10}.\)
\(=\frac{11-\sqrt{10}}{6}\)
\(b,=\frac{\left(9-2\sqrt{2}\right)\left(3\sqrt{6}+2\sqrt{2}\right)}{\left(3\sqrt{6}-2\sqrt{2}\right)\left(3\sqrt{6}+2\sqrt{2}\right)}=\frac{\left(9-2\sqrt{2}\right)\left(3\sqrt{6}+2\sqrt{2}\right)}{54-8}\)
\(=\frac{\left(9-2\sqrt{2}\right)\left(3\sqrt{6}+2\sqrt{2}\right)}{46}\)
Bài 1 :
a, \(\frac{2ab}{\sqrt{a}+\sqrt{b}}=\frac{2ab\left(\sqrt{a}-\sqrt{b}\right)}{\left(\sqrt{a}+\sqrt{b}\right)\left(\sqrt{a}-\sqrt{b}\right)}=\frac{2ab\left(\sqrt{a}-\sqrt{b}\right)}{a-b}\)
b, \(\frac{2\sqrt{10}-5}{4-\sqrt{10}}=\frac{\left(2\sqrt{10}-5\right)\left(4+\sqrt{10}\right)}{\left(4-\sqrt{10}\right)\left(4+\sqrt{10}\right)}=\frac{\sqrt{10}}{2}\)
c, \(\frac{9-2\sqrt{3}}{3\sqrt{6}-2\sqrt{2}}=\frac{\left(9-2\sqrt{3}\right)\left(3\sqrt{6}+2\sqrt{2}\right)}{\left(3\sqrt{6}-2\sqrt{2}\right)\left(3\sqrt{6}+2\sqrt{2}\right)}=\frac{\sqrt{6}}{2}\)
2. \(\frac{1}{\sqrt{3}-\sqrt{2}}-\frac{2}{\sqrt{7}+\sqrt{5}}-\frac{3}{\sqrt{7-2\sqrt{10}}}+\frac{4}{\sqrt{10+2\sqrt{21}}}\)
\(=\frac{\sqrt{3}+\sqrt{2}}{3-2}-\frac{2.\left(\sqrt{7}-\sqrt{5}\right)}{7-5}-\frac{3}{\sqrt{2-2\sqrt{10}+5}}+\frac{4}{\sqrt{3+2\sqrt{21}+7}}\)
\(=\left(\sqrt{3}+\sqrt{2}\right)-\frac{2\left(\sqrt{7}-\sqrt{5}\right)}{2}-\frac{3}{\sqrt{\left(\sqrt{2}-\sqrt{5}\right)^2}}+\frac{4}{\sqrt{\left(\sqrt{3}+\sqrt{7}\right)^2}}\)
\(=\left(\sqrt{3}+\sqrt{2}\right)-\left(\sqrt{7}-\sqrt{5}\right)-\frac{3}{\left|\sqrt{2}-\sqrt{5}\right|}+\frac{4}{\left|\sqrt{3}+\sqrt{7}\right|}\)
\(=\left(\sqrt{3}+\sqrt{2}\right)-\left(\sqrt{7}-\sqrt{5}\right)-\frac{3}{\sqrt{5}-\sqrt{2}}+\frac{4}{\sqrt{3}+\sqrt{7}}\)
\(=\left(\sqrt{3}+\sqrt{2}\right)-\left(\sqrt{7}-\sqrt{5}\right)-\frac{3.\left(\sqrt{5}+\sqrt{2}\right)}{5-2}+\frac{4.\left(\sqrt{7}-\sqrt{3}\right)}{7-3}\)
\(=\left(\sqrt{3}+\sqrt{2}\right)-\left(\sqrt{7}-\sqrt{5}\right)-\frac{3\left(\sqrt{5}+\sqrt{2}\right)}{3}+\frac{4\left(\sqrt{7}-\sqrt{3}\right)}{4}\)
\(=\left(\sqrt{3}+\sqrt{2}\right)-\left(\sqrt{7}-\sqrt{5}\right)-\left(\sqrt{5}+\sqrt{2}\right)+\left(\sqrt{7}-\sqrt{3}\right)\)
\(=\sqrt{3}+\sqrt{2}-\sqrt{7}+\sqrt{5}-\sqrt{5}-\sqrt{2}+\sqrt{7}-\sqrt{3}=0\)