Question

[nguyễn văn tý]

1)\(\left|0,5-\dfrac{1}{3}+x\right|=-\left|y\right|-\dfrac{1}{4}\)

2)\(\left|x+\dfrac{13}{7}\right|+\left|z-2008\right|=0\)

Answer 1

[ngonhuminh]

cu the de bat lam gi

Answer 2

[Đạt Trần]

dễ lắm

1) \(\left|0,5-\dfrac{1}{3}+x\right|=-\left|y\right|-\dfrac{1}{4}\)

\(\Leftrightarrow\left|0,5-\dfrac{1}{3}+x\right|=-\left(\left|y\right|+\dfrac{1}{4}\right)\)

Vì \(\left|y\right|\ge0\forall y\Rightarrow-\left(\left|y\right|+\dfrac{1}{3}\right)< 0\forall y\)

VT>0; VP<0=> PT vô nghiệm

2

Dấu bằng xảy ra \(\Leftrightarrow\)\(\left\{{}\begin{matrix}x+\dfrac{13}{7}=0\\z-2008=0\end{matrix}\right.\)\(\Leftrightarrow z=2008;x=-\dfrac{13}{7}\)