Question

[Nguyễn Thị Phương Linh]

1,\(A=\dfrac{-2}{4}+\dfrac{2}{7}-\dfrac{5}{28}\)

2,\(B=\left(\dfrac{5}{7}\cdot0,6-5:3\dfrac{1}{2}\right)\cdot\left(40\%-1,4\right)\cdot\left(-2\right)^3\)

Answer 1

[nguyen thi vang]

1, \(A=\dfrac{-2}{4}+\dfrac{2}{7}-\dfrac{5}{28}\)

\(A=\dfrac{-1}{2}+\dfrac{2}{7}-\dfrac{5}{28}\)

\(A=\dfrac{-14+8-5}{28}=\dfrac{-11}{28}\)

2, \(B=\left(\dfrac{5}{7}.0,6-5:3\dfrac{1}{2}\right).\left(40\%-1,4\right).\left(-2\right)^3\)

\(B=\dfrac{-13}{14}.\left(-1\right).8=\dfrac{52}{7}\)