Question

[Nguyễn Ngọc Hải Băng]

1. Giải phương trình

a) \(\frac{2}{x^2-x-6}+\frac{x+1}{x^2+x-12}=\frac{x}{x^2+6x+8}\)

b) \(\frac{2x-5}{x^2+5x-36}-\frac{x-6}{x^2+3x-28}=\frac{x+8}{x^2+16x+63}\)

c) \(\frac{x-2}{4x^2-29x+30}-\frac{x+1}{20x^2-13x-15}=\frac{x+2}{5x^2-274x+18}\)

Answer 1

[hattori heiji]

\(\dfrac{2}{x^2-x-6}+\dfrac{x+1}{x^2+x-12}=\dfrac{x}{x^2+6x+8}\)

\(\Leftrightarrow\dfrac{2}{\left(x-3\right)\left(x+2\right)}+\dfrac{x+1}{\left(x-3\right)\left(x+4\right)}=\dfrac{x}{\left(x+2\right)\left(x+4\right)}\)

=> 2(x+4)+(x+1)(x+2)=x(x-3)

⇔2x+8+x²+2x+x+2=x²-3x

⇔x²+5x+10=x²-3x

⇔x²-x²+5x+3x=-10

⇔8x=-10

\(\Leftrightarrow\dfrac{-5}{4}\)

Vậy S={-\(\dfrac{5}{4}\)}