Bài 1.Rút gọn
a,4.7/9.32
b,2.5.13/26.35
c,3.21/14.15
d,9.6-9.3/18
e,17.5-17/3-20
f,49+7.49
Bài 2 .Đổi ra m2 viết dưới dạng phân số tối giản
a,45 dm2 b, 300cm2
c, 57500 mm2
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B1: \(45dm^2=0,45m^2\)
\(300cm^2=0,03m^2\)
\(57500mm^2=0,0575m^2\)
B2: chiếm \(\dfrac{24-9}{24}=\dfrac{5}{8}\)(ngày)
B3: lượng nước cần bơm tiếp cho đầy bể bằng
\(\dfrac{5000-3500}{5000}=\dfrac{3}{10}\)(bể)
a) 4.79.32=4.79.4.8=79.8=772
b) 3.2114.15=3.3.72.7.3.5=32.5=310
c) 2.5.1326.35=2.5.132.13.5.7=17
d) 9.6–9.318=9.(6–3)9.2=6–32=32
e) 17.5–173–20=17.(5–1)–17=5–1–1=–4
f)
a) \(\dfrac{4.7}{9.32}=\dfrac{4.7}{9.4.8}=\dfrac{7}{72}\) b) \(\dfrac{3.21}{14.15}=\dfrac{3.7.3}{7.2.3.5}=\dfrac{3}{10}\)
c) \(\dfrac{2.5.13}{26.35}=\dfrac{2.5.13}{2.13.5.7}=\dfrac{1}{7}\) d)\(\dfrac{9.6-9.3}{18}\) \(=\dfrac{9.\left(6-3\right)}{9.2}=\dfrac{9.3}{9.2}=\dfrac{3}{2}\)
e) \(\dfrac{17.5-17}{3-20}=\dfrac{17.\left(5-1\right)}{-17}=-\dfrac{17.4}{17}=-4\) f) \(\dfrac{49+7.49}{49}=\dfrac{49.\left(1+7\right)}{49}=8\)
25dm2=1/4m2
36dm2=9/25m2
450cm=9/200m2
575cm2= xin lỗ i nha chặp nữa mình giải
1/ 25 dm2=\(\dfrac{1}{4}m^2\)
2/ 36 dm2 =\(\dfrac{9}{25}m^2\)
3/ 450 cm2 =\(\dfrac{9}{200}m^2\)
4/ 575 cm2=\(\dfrac{23}{40}m^2\)
1) \(25dm^2=0.25m^2\)
2) \(36dm^2=0,36m^2\)
3) \(450cm^2=\dfrac{9}{200}m^2\)
4) \(575cm^2=\dfrac{23}{400}m^2\)
\(\frac{4\cdot7}{9\cdot32}=\frac{4\cdot7}{9\cdot8\cdot4}=\frac{7}{8\cdot9}=\frac{7}{72}\)
\(\frac{2\cdot5\cdot13}{26\cdot35}=\frac{2\cdot5\cdot13}{2\cdot13\cdot7\cdot5}=\frac{1}{7}\)
\(\frac{3\cdot21}{14\cdot15}=\frac{3\cdot3\cdot7}{2\cdot7\cdot3\cdot5}=\frac{3}{2\cdot5}=\frac{3}{10}\)
\(\frac{9\cdot6-9\cdot3}{18}=\frac{9\cdot\left(6-3\right)}{9\cdot2}=\frac{9\cdot3}{9\cdot2}=\frac{3}{2}\)
\(\frac{17\cdot5-17}{3-20}=\frac{17\cdot\left(5-1\right)}{-17}=\frac{17\cdot4}{17\cdot\left(-1\right)}=\frac{4}{-1}=-4\)
\(45dm^2=0,45m^2\)
\(300cm^2=0,03m^2\)
\(57500mm^2=0,0575m^2\)