giải phương trình sau:
a. \(\frac{6x+1}{x^2-7x+10} +\frac{5}{x-2}=\frac{3}{x-5}\)
b.\(\frac{2}{x^2-4}-\frac{x-1}{x\left(x-2\right)}+\frac{x-4}{x\left(x+2\right)}=0\)
c. \(\frac{1}{3-x}-\frac{1}{x+1}=\frac{x}{x-3}-\frac{\left(x-1\right)^2}{x^2-2x-3}\)
d.\(\frac{1}{x-2}-\frac{6}{x+3}=\frac{5}{6-x^2-x}\)
e.\(\frac{2}{x+2}-\frac{2x^2+16}{x^3+8}=\frac{5}{x^2-2x-3}\)
f. \(\frac{x+1}{x^2+x+1}-\frac{x-1}{x^2-x+1}=\frac{2\left(x+2\right)^2}{x^6-1}\)