1.tìm x thuộc z, biết
a. x-96=(443-x)-15 b. (x-12)-15=(20-7)-(18+x)
c. x.(x-10)=0 d. 17.(3x-6).(2x-8)=0
e. -x.(x+7).(x-4)=0 f. |-x+1| . |x-2|=0
i(3x-7)+2.(5-2x)+5x=19 l. |2x-2|-3x+1=-2
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a) -2 (x+6)+6 (x-10)=8
-2.x + (-2).6 + 6.x - 6.10 = 8
-2x + (-12) + 6x - 60 = 8
-2x + 6x + [60 + (-12)] = 8
4x + 48 = 8
4x = 8 - 48
4x = -40
x = -40 : 4
x = -10
vậy_____
b) ( x-12)-15=(20-7) - (18-x)
x - 12 - 15 = 13 - 18 + x
x - 27 = -5 + x
x - x = -5 + 27
0x = 22
x = 22 : 0
=> x ∈ ∅
c)2(5+3x)+x=31
2.5 + 2.3x + x = 31
10 + 6x + x = 31
6x + x = 31 - 10
7x = 21
x = 21 : 7
x = 3
vậy_____
d) -x (x+7) ( x-4) =0
=> -x = 0 hoặc x+ 7 = 0 hoặc x - 4 = 0
=> x = 0 hoặc x = 0 - 7 hoặc x = 0 + 4
=> x = 0 hoặc x = -7 hoặc x = 4
vậy_____
e) x-96 = (443 - x) - 15
x - 96 = 443 - x - 15
x - 96 = (443 - 15) - x
x - 96 = 428 - x
x + x = 428 + 96
2x = 524
x = 524 : 2
x = 262
vậy_____
a) x - 96 = (433 - x) - 15
x - 96 = 433 - x - 15
2x = 433 - 15 + 96
2x = 514
x = 257
b) 7x (-x-10) = 0
\(\Leftrightarrow\orbr{\begin{cases}7x=0\\-x-10=0\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=-10\end{cases}}\)
c) 17 (3x - 6) (2x - 8) = 0
(3x - 6) (2x - 8) = 0
\(\Leftrightarrow\orbr{\begin{cases}3x-6=0\\2x-8=0\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}3x=6\\2x=8\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x=2\\x=4\end{cases}}\)
a) \(5\left(x-7\right)=0\)
\(\Rightarrow x-7=0\)
\(\Rightarrow x=7\)
b) \(25\left(x-4\right)=0\)
\(\Rightarrow x-4=0\)
\(\Rightarrow x=4\)
c) \(\left(34-2x\right)\left(2x-6\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)
d) \(\left(2019-x\right)\left(3x-12\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2019\\3x=12\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2019\\x=\dfrac{12}{3}=4\end{matrix}\right.\)
e) \(57\left(9x-27\right)=0\)
\(\Rightarrow9x-27=0\)
\(\Rightarrow9\left(x-3\right)=0\)
\(\Rightarrow x-3=0\)
\(\Rightarrow x=3\)
a) 5.(x-7)=0⇔x-7=0⇔x=7
b) 25(x-4)=0⇔x-4=0⇔x=4
c) (34-2x).(2x-6)=0
⇔ 34-2x=0 hoặc 2x-6=0
⇔2x=34 hoặc 2x=6
⇔ x=17 hoặc x=3
d) (2019-x).(3x-12)=0
⇔ 2019-x=0 hoặc 3x-12=0
⇔ x=2019 hoặc x=4
e) 57.(9x-27)=0
⇔ 9x-27=0
⇔ x=3
f) 25+(15-x)=30
⇔ 15-x=5
⇔ x=10
g) 43-(24-x)=20
⇔ 24-x=23
⇔ x=1
h) 2.(x-5)-17=25
⇔ 2(x-5)=42
⇔x-5=21
⇔ x=26
i) 3(x+7)-15=27
⇔ 3(x+7)=42
⇔ x+7=14
⇔ x=7
j) 15+4(x-2)=95
⇔ 4(x-2)=80
⇔ x-2=20
⇔ x=22
k) 20-(x+14)=5
⇔ x+14=15
⇔ x=1
l) 14+3(5-x)=27
⇔ 3(5-x)=13
⇔ 5-x=13/3
⇔ x=5-13/3
⇔ x=2/3
a, x - 96 = ( 443 - x ) - 15
x - 96 = 443 - x - 15
x - 96 = 428 - x
x + x = 428 + 96
2x = 524
x = 262
b, ( x - 12 ) - 15 = ( 20 - 7 ) - ( 18 - x )
x - 12 - 15 = 13 - 18 + x
x - 27 = - 5 + x
x - x = - 5 + 27
0x = 22
=> ko có giá trị nào thõa mãn
c, 353 - x = 46 + ( 3x - 21 )
353 - x = 46 + 3x - 21
353 - x = 25 + 3x
- x - 3x = 25 - 353
- 4x = - 328
x = 82
d, - ( x + 81 ) = ( 2x +12 ) - ( 5 + x )
- x - 81 = 2x + 12 - 5 - x
- x - 81 = x + 7
- x - x = 7 + 81
- 2x = 88
x = - 44
e, ( - x + 821 + 534 ) = 499 + ( x - 84 )
- x + 1355 = 499 + x - 84
- x - x = 499 - 84 - 1355
- 2x = - 940
x = 470
g, x + 53 = ( 400 - 9x ) - 447
x + 53 = 400 - 9x - 447
x + 53 = - 47 - 9x
x + 9x = - 47 - 53
10x = -100
x = - 10
a) x - 96 = (443 - x) - 15
x - 96 = 443 - x - 15
x + x = 443 -15 + 96
2x = 524
x = 524 : 2
x = 262
b) (x -12) - 15 = (20 - 7) - (18 + x)
x - 12 - 15 = 20 - 7 - 18 - x
x + x = 20 - 7 - 18 + 12 + 15
2x = 22
x = 22 : 2
x = 11
c) 311 - x + 82 = 46 + (x - 21)
311 - x + 82 = 46 + x - 21
-x - x = 46 - 21 - 311 - 81
-2x = -367
x = -367 : (-2)
x = 183,5
d) -(x - 3 + 85) = (x + 70 - 71) - 5
-x + 3 - 85 = x + 70 - 71 - 5
-x - x = 70 - 71 - 5 - 3 + 85
-2x = 76
x = 76 : (-2)
x = -38
e,f làm tương tự
a) x - 96 = (443 - x) - 15
x - 96 = 443 - x - 15
x + x = 443 -15 + 96
2x = 524
x = 524 : 2
x = 262
b) (x -12) - 15 = (20 - 7) - (18 + x)
x - 12 - 15 = 20 - 7 - 18 - x
x + x = 20 - 7 - 18 + 12 + 15
2x = 22
x = 22 : 2
x = 11
c) 311 - x + 82 = 46 + (x - 21)
311 - x + 82 = 46 + x - 21
-x - x = 46 - 21 - 311 - 81
-2x = -367
x = -367 : (-2)
x = 183,5
d) -(x - 3 + 85) = (x + 70 - 71) - 5
-x + 3 - 85 = x + 70 - 71 - 5
-x - x = 70 - 71 - 5 - 3 + 85
-2x = 76
x = 76 : (-2)
x = -38
e,f làm tương tự
a) x - (11 - x) = -48 + (-12 + x)
x - 11 + x = -48 + (-12) + x
x + x - x = -48 + (-12) + 11
x + 0 = (-60) + 11
x = -49
b) (15 - x) + (x - 12) = 7 - (-8 + x)
15 - x + x - 12 = 7 + 8 + x
15 - x + x - 12 = 15 + x
x + x - x = 15 - 15 + 12
x + 0 = 0 + 12
x = 12
c) (x - 12) - (2x + 31) = -6 - 5
x - 12 - 2x - 31 = -1
x - 12 - 2x = -1 + 31
x - 12 - 2x = 30
x - 2x = 30 + 12
-1x = 42
=> x = -42
d) |x + 5| - (-17) = 20
=> |x + 5| + 17 = 20
=> |x + 5| = 20 - 17
=> |x + 5| = 3
=> \(\orbr{\begin{cases}x+5=3\\x+5=-3\end{cases}}\)
=> \(\orbr{\begin{cases}x=3-5\\x=-3-5\end{cases}}\)
=> \(\orbr{\begin{cases}x=-2\\x=-8\end{cases}}\)
12x2 - 3x = 0
=> 12x2 - 3x = (22 . 3x2) - 3x = 0
=> 3x . (4x - 1) = 0
=> 3x . 4x - 3x . 1 = 0
=> 3x . 4x - 3x = 0
=> 12x - 3x = 0
=> 4x =0
=> x = 0
`@` `\text {Ans}`
`\downarrow`
`c)`
`( 34 - 2x ) . ( 2x - 6 ) = 0`
`=>`\(\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=34\div2\\x=6\div2\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)
Vậy, `x \in {17; 3}`
`d)`
`( 2019 - x ) . ( 3x - 12 ) =0` `?`
`=>`\(\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019-0\\3x=12\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019\\x=12\div3\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)
Vậy, `x \in {2019; 4}`
`e) `
`57 . ( 9x - 27 ) = 0`
`=>`\(9x-27=0\div57\)
`=> 9x - 27 = 0`
`=> 9x = 27`
`=> x = 27 \div 9`
`=> x = 3`
Vậy, `x = 3`
`f)`
`25 + ( 15 - x ) = 30`
`=> 15 - x = 30 - 25`
`=> 15 - x = 5`
`=> x = 15 -5 `
`=> x = 10`
Vậy, `x = 10`
`g) `
`43 - ( 24 - x ) = 20`
`=> 24 - x = 43 - 20`
`=> 24 - x = 23`
`=> x = 24 - 23`
`=> x = 1`
Vậy, `x = 1`
`h) `
`2 . ( x - 5 ) - 17 = 25`
`=> 2 ( x - 5) = 25+17`
`=> 2 ( x - 5) = 42`
`=> x - 5 = 42 \div 2`
`=> x - 5 = 21`
`=> x = 21 + 5`
`=> x = 26`
Vậy, `x = 26`
`i)`
`3 . ( x + 7 ) - 15 = 27`
`=> 3(x + 7) = 27 + 15`
`=> 3(x + 7) = 42`
`=> x +7 = 42 \div 3`
`=> x + 7 = 14`
`=> x = 14 - 7`
`=> x = 7`
Vậy, `x = 7`
`j)`
`15 + 4 . ( x - 2 ) = 95`
`=> 4(x - 2) = 95 - 15`
`=> 4(x - 2) = 80`
`=> x - 2 = 80 \div 4`
`=> x - 2 = 20`
`=> x = 20 + 2`
`=> x = 22`
Vậy, `x = 22`
`k)`
`20 - ( x + 14 ) = 5`
`=> x + 14 = 20 - 5`
`=> x + 14 = 15`
`=> x = 15 - 14`
`=> x = 1`
Vậy, `x = 1`
`l) `
`14 + 3 . ( 5 - x ) = 27`
`=> 3(5 - x) = 27 - 14`
`=> 3(5 - x) = 13`
`=> 5 - x = 13 \div 3`
`=> 5 - x = 13/3`
`=> x = 5- 13/3`
`=> x = 2/3`
Vậy, `x = 2/3.`
`@` `\text {Kaizuu lv uuu}`
a, x - 96 = (443 - x) - 15
<=>x - 96 = 443 - x - 15
<=>x + x = 443 - 15 + 96
<=>2x = 524
<=>x = 524 : 2
<=>x = 262
b, (x - 12) - 15 = (20 - 7) - (18 + x)
<=>x - 12 - 15 = 20 - 7 - 18 - x
<=>x + x = 20 - 7 - 18 + 12 + 15
<=>2x = 22
<=> x = 22 : 2
<=> x = 11