Tìm số tự nhiên n,biết rằng:
a/ 2 mũ n = 16 b/ 4 mũ n = 64 c/ 15 mũ n = 225
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a ) 2n = 16
2.2.2.2 = 16 nên n = 4
Vậy : 24 = 16
b ) 4n = 64
4.4.4 = 64 nên n = 3
Vậy : 43 = 64
c ) 15n = 225
15.15 = 225 nên n = 2
Vậy : 152 = 225
a, 2^n= 16
2^n= 2^4
=> n=4
b, 4^n= 64
4^n= 4^3
=> n=3
c, 15^n =225
15^n= 15^2
=> n=2
a) \(2^n:4=16\Rightarrow2^n:2^2=2^4\Rightarrow2^{n-2}=2^4\Rightarrow n-2=4\Rightarrow n=6\)
b) \(6\cdot2^n+3\cdot2^n=9\cdot2^9\)
=> \(\left(6+3\right)\cdot2^n=9\cdot2^9\)
=> \(9\cdot2^n=9\cdot2^9\Rightarrow n=9\)
c) \(3^n:3^2=243\)
=> \(3^{n-2}=3^5\)
=> n - 2 = 5 => n = 7
d) 25 < 5n < 3125
=> 52 < 5n < 55
=> n \(\in\){3;4}
a) \(\frac{16}{2^n}=2\)
=> 2.2n = 16
=> 21+n = 24
=> 1 + n = 4
=> n = 4 - 1
=> n = 3
Vậy n = 3
b) \(\frac{\left(-3\right)^n}{81}=-27\)
=> (-3)n = -27.81
=> (-3)n = -33.34
=> (-3)n = (-3)7
=> n = 7
Vậy n = 7
c) 8n : 2n = 4
=> (8 : 2)n = 4
=> 4n = 41
=> n = 1
Vậy n = 1
a)\(32^n=64^5\)
\(=>\left(2^5\right)^n=\left(2^6\right)^5\)
\(2^{5.n}=2^{5.6}\)
\(=>n=6\)
b)\(16^n=64^8\)
\(=>\left(4^2\right)^n=\left(4^3\right)^8\)
\(4^{2.n}=4^{3.8}\)
\(=>2.n=3.8\)
\(2.n=24\)
\(n=24:2=12\)
chúc bạn học tốt nha
a) \(11^n=1331\)
\(\Rightarrow11^n=11^3\)
\(\Rightarrow n=3\)
b) \(n^3=125\)
\(\Rightarrow n^3=5^3\)
\(\Rightarrow n=5\)
c) \(5^4=n\)
\(\Rightarrow625=n\)
\(\Rightarrow n=625\)
d) \(\left(n+1^2\right)=9\)
\(\Rightarrow n+1=9\)
\(\Rightarrow n=9-1\)
\(\Rightarrow n=8\)
a) 11^n = 1331
⇒ 11^n = 11^3
⇔ n = 3
b) n^ 3 = 125
⇒ n^3 = 5^3
⇔ n = 5
c) 5^4 = n
⇒ n = 625
d) ( n + 1^2 ) = 9
⇒ ( n + 1 ) = 9
⇒ n = 8
\(a,2^n=16\Leftrightarrow2^n=2^4\Leftrightarrow n=4\)
\(3^n=243\Rightarrow3^n=3^5\Leftrightarrow n=5\)
\(b,4^n=4096\Rightarrow4^n=4^6\Leftrightarrow n=6\)
\(5^n=15625\Rightarrow5^n=5^6\Leftrightarrow n=6\)
\(c,6^{n+3}=216\Rightarrow6^{n+3}=6^3\Rightarrow n+3=3\Leftrightarrow n=0\)
\(4^{n-1}=1024\Rightarrow4^{n-1}=4^5\Rightarrow n-1=5\Leftrightarrow n=6\)
\(a.\) \(2^n=16\Rightarrow2^n=2^4\Leftrightarrow n=4\)
\(3^n=243\Rightarrow3^n=3^5\Leftrightarrow n=5\)
\(b.\) \(4^n=4096\Rightarrow4^n=4^6\Rightarrow n=6\)
\(5^n=15625\Rightarrow5^n=5^6\Rightarrow n=6\)
\(c.\) \(6^{n+3}=216\Rightarrow6^{n+3}=6^3\Rightarrow n+3=3\Rightarrow n=0\)
\(4^{n-1}=1024\Rightarrow4^{n-1}=4^5\Rightarrow n-1=5\Rightarrow n=6\)
Bài 6 :
a) \(\dfrac{625}{5^n}=5\Rightarrow\dfrac{5^4}{5^n}=5\Rightarrow5^{4-n}=5^1\Rightarrow4-n=1\Rightarrow n=3\)
b) \(\dfrac{\left(-3\right)^n}{27}=-9\Rightarrow\dfrac{\left(-3\right)^n}{\left(-3\right)^3}=\left(-3\right)^2\Rightarrow\left(-3\right)^{n-3}=\left(-3\right)^2\Rightarrow n-3=2\Rightarrow n=5\)
c) \(3^n.2^n=36\Rightarrow\left(2.3\right)^n=6^2\Rightarrow\left(6\right)^n=6^2\Rightarrow n=6\)
d) \(25^{2n}:5^n=125^2\Rightarrow\left(5^2\right)^{2n}:5^n=\left(5^3\right)^2\Rightarrow5^{4n}:5^n=5^6\Rightarrow\Rightarrow5^{3n}=5^6\Rightarrow3n=6\Rightarrow n=3\)
Bài 7 :
a) \(3^x+3^{x+2}=9^{17}+27^{12}\)
\(\Rightarrow3^x\left(1+3^2\right)=\left(3^2\right)^{17}+\left(3^3\right)^{12}\)
\(\Rightarrow10.3^x=3^{34}+3^{36}\)
\(\Rightarrow10.3^x=3^{34}\left(1+3^2\right)=10.3^{34}\)
\(\Rightarrow3^x=3^{34}\Rightarrow x=34\)
b) \(5^{x+1}-5^x=100.25^{29}\Rightarrow5^x\left(5-1\right)=4.5^2.\left(5^2\right)^{29}\)
\(\Rightarrow4.5^x=4.25^{2.29+2}=4.5^{60}\)
\(\Rightarrow5^x=5^{60}\Rightarrow x=60\)
c) Bài C bạn xem lại đề
d) \(\dfrac{3}{2.4^x}+\dfrac{5}{3.4^{x+2}}=\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{10}}\)
\(\Rightarrow\dfrac{3}{2.4^x}-\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{x+2}}-\dfrac{5}{3.4^{10}}=0\)
\(\Rightarrow\dfrac{3}{2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)+\dfrac{5}{3.4^2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)=0\)
\(\Rightarrow\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)\left(\dfrac{3}{2}+\dfrac{5}{3.4^2}\right)=0\)
\(\Rightarrow\dfrac{1}{4^x}-\dfrac{1}{4^8}=0\)
\(\Rightarrow\dfrac{4^8-4^x}{4^{x+8}}=0\Rightarrow4^8-4^x=0\left(4^{x+8}>0\right)\Rightarrow4^x=4^8\Rightarrow x=8\)
a/ 2n = 16
Vì 2.2.2.2 = 16
=> n = 4
b/ 4n = 64
Vì 4.4.4 = 64
=> n = 3
c/ 15n = 225
Vì 15 . 15 = 225
=> n = 2
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