-2023 -(-2023+3^17:3^15)-1^2023 thực hiện phép tính giúp vs ạ
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
1-2+3-4+...+2021-2022+2023
=(1-2)+(3-4)+...+(2021-2022)+2023
=(-1)+(-1)+(-1)+...+(-1)+2023
=(-1011)+2023
=1012
a, \(\dfrac{7}{22}\) - \(\dfrac{15}{23}\) + \(\dfrac{2022}{2023}\) - \(\dfrac{8}{23}\) + \(\dfrac{15}{22}\)
= ( \(\dfrac{7}{22}\) + \(\dfrac{15}{22}\)) - ( \(\dfrac{15}{23}+\dfrac{18}{23}\)) + \(\dfrac{2022}{2023}\)
= \(\dfrac{22}{22}\) - \(\dfrac{23}{23}\) + \(\dfrac{2022}{2023}\)
= 1 - 1 + \(\dfrac{2022}{2023}\)
= \(\dfrac{2022}{2023}\)
b, - \(\dfrac{2}{11}\) + 5\(\dfrac{5}{6}\) ( 14\(\dfrac{1}{5}\) - 11\(\dfrac{1}{5}\)): 5\(\dfrac{1}{2}\)
= - \(\dfrac{2}{11}\) + \(\dfrac{35}{6}\) ( \(\dfrac{71}{5}\) - \(\dfrac{56}{5}\)) : \(\dfrac{11}{2}\)
= - \(\dfrac{2}{11}\) + \(\dfrac{35}{6}\) . \(\dfrac{15}{5}\) : \(\dfrac{11}{2}\)
= - \(\dfrac{2}{11}\) + \(\dfrac{35}{2}\) \(\times\) \(\dfrac{2}{11}\)
= - \(\dfrac{2}{11}\) + \(\dfrac{35}{11}\)
= \(\dfrac{33}{11}\)
= 3
c, 2000 + { 20 - [ 4.20220 - (32 + 5):2] }
= 2000 + { 20 - [ 4.1 - (9+5):2]}
= 2000 + { 20 - [ 4 - 14 : 2 ]}
= 2000 + { 20 - [ 4 -7]}
= 2000 + { 20 - (-3)}
= 2000 + 23
= 2023
A) 195 x 63 + 37 x195
195 x ( 63 + 37 ) = 195 x 100
= 19500
B) 7^12 : 7^10 - 36 : 3^2
= 7^12-10 - 36 : 9
= 7^2 - 4 = 49 - 4 = 45
C) 180 - [130-(12-10)^3] + 2023^0
= 180 -(130-2^3)+1
= 180-130+8+1
= 50 + 8+1 = 59
\(a,195.63+37.195\)
\(=195\left(63+37\right)\)
\(=195.100\)
\(=19500\)
\(b,7^{12}:7^{10}-36:3^2\)
\(=7^2-2^2.3^2:3^2\)
\(=7^2-2^2\)
\(=49-4=44\)
\(c,180-\left[130-\left(12-10\right)^3\right]+2023^0\)
\(=180-\left[130-2^3\right]+1\)
\(=180-\left(130-8\right)+1\)
\(=180-122+1\)
\(=59\)
Có gì k hiểu thì ib nhá
A) Do 34 < 36 nên 34³⁴ < 34³⁶
B) 1²⁰²³ = 1
2023⁰ = 1
Vậy 1²⁰²³ = 2023⁰
C) Do 45 < 47 nên 45²⁰²³ < 47²⁰²³
-2023 - (-2023 + 317 : 315) - 12023
= -2023 - (-2023 + 32) - 1
= -2023 - (-2023 + 9) - 1
= -2023 - (-2014) - 1
= -2023 + 2014 - 1
= -9 - 1 = -10