Thay tí số giữa các số hữu tỉ bằng tỉ số giữa các số nguyên:
a,10/12 : 6/25 b,1,7 : 2,85
c,1/5 : 0,25 d,a/b : c/d (a,b,c,d thuộc Z)
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a) \(2.04:\left(-3.12\right)=\dfrac{204}{-312}=\dfrac{-17}{26}\)
b) \(\left(-1\dfrac{1}{2}\right):1.25=\dfrac{-3}{2}:\dfrac{5}{4}=\dfrac{-3}{2}\cdot\dfrac{4}{5}=\dfrac{-12}{10}=\dfrac{-6}{5}\)
c) \(4:5\dfrac{3}{4}=4:\dfrac{23}{4}=4\cdot\dfrac{4}{23}=\dfrac{16}{23}\)
d) \(10\dfrac{3}{7}:5\dfrac{3}{14}=\dfrac{73}{7}:\dfrac{73}{14}=\dfrac{2}{1}\)
a) \(3,7:4,5=\dfrac{3,7}{4,5}=\dfrac{37}{45}\)
b) \(2\dfrac{1}{3}:4\dfrac{2}{3}=\dfrac{7}{3}:\dfrac{14}{3}=\dfrac{7}{3}\times\dfrac{3}{14}=\dfrac{1}{2}\)
c) \(\dfrac{3}{8}:0,7=\dfrac{3}{8}:\dfrac{7}{10}=\dfrac{3}{8}\times\dfrac{10}{7}=\dfrac{15}{28}\)
d) \(5\dfrac{1}{7}:2\dfrac{1}{3}=\dfrac{36}{7}:\dfrac{7}{3}=\dfrac{36}{7}\times\dfrac{3}{7}=\dfrac{108}{49}\)
`a)10/16 : 4/21`
`=105/32`
`=105:32`
`b)1,3:2,75`
`=26/55`
`=26:55`
`c)[-2]/5:0,25`
`=[-8]/5`
`=-8:5`
`a,` \(\dfrac{10}{16}\div\dfrac{4}{21}=\dfrac{5}{8}\div\dfrac{4}{21}=\dfrac{105}{32}=105\div32\)
`b,` \(1,3\div2,75=\dfrac{13}{10}\div\dfrac{11}{4}=\dfrac{26}{55}=26\div55\)
`c,` \(-\dfrac{2}{5}\div0,25=-\dfrac{2}{5}\div\dfrac{1}{4}=-\dfrac{8}{5}=-8\div5\)
\(\begin{array}{l}a)\dfrac{{10}}{{16}}:\dfrac{4}{{21}} = \dfrac{{10}}{{16}}.\dfrac{{21}}{4} = \dfrac{{105}}{{32}} = 105:32;\\b)1,3:2,75 = \dfrac{{1,3}}{{2,75}} = \dfrac{{130}}{{275}} = \dfrac{{26}}{{55}} = 26:55;\\c)\dfrac{{ - 2}}{5}:0,25 = \dfrac{{ - 2}}{5}:\dfrac{1}{4} = \dfrac{{ - 2}}{5}.\dfrac{4}{1} = \dfrac{{ - 8}}{5} = ( - 8):5\end{array}\)
a. \(\frac{10}{12}\div\frac{6}{25}=\frac{5}{6}\times\frac{25}{6}=\frac{125}{36}\)
b. \(1,7\div2,85=\frac{1,7}{2,85}=\frac{1,7\times100}{2,85\times100}=\frac{170}{285}\)
c, \(\frac{1}{5}\div0,25=\frac{1}{5}\div\frac{1}{4}=\frac{1}{5}\times4=\frac{4}{5}\)
d, a/b : c/d = (a*b*d) : (c*b*d)