Tim x: 18/5 * x = 9/7:14/5
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a: \(=\dfrac{17}{19}\cdot\dfrac{19}{17}\cdot\dfrac{4}{5}=\dfrac{4}{5}\)
b: \(=\dfrac{14}{7}\cdot\dfrac{7}{6}=2\cdot\dfrac{7}{6}=\dfrac{14}{6}=\dfrac{7}{3}\)
c: =13/14(4/5+1/5)=13/14
\(\dfrac{17}{19}\times\dfrac{12}{15}\times\dfrac{19}{17}.\\ =\dfrac{17}{19}\times\dfrac{19}{17}\times\dfrac{12}{15}.\\ =1\times\dfrac{12}{15}=\dfrac{12}{15}.\\ \left(\dfrac{5}{7}+\dfrac{9}{7}\right)\times\dfrac{21}{18}.\\ =2\times\dfrac{7}{6}=\dfrac{7}{3}.\\ \dfrac{4}{5}\times\dfrac{13}{14}+\dfrac{13}{14}\times\dfrac{1}{5}.\\ =\left(\dfrac{4}{5}+\dfrac{1}{5}\right)\times\dfrac{13}{14}.\\ =1\times\dfrac{13}{14}.\\ =\dfrac{13}{14}.\)
\(\frac{9}{14}-\frac{x}{7}:\frac{5}{3}=\frac{3}{14}\Leftrightarrow\frac{9}{14}-\frac{3x}{35}=\frac{3}{14}\Leftrightarrow\frac{3x}{35}=\frac{3}{7}\Leftrightarrow3x=15\Leftrightarrow x=5\)
\(x-14=3x+18\)
\(\Leftrightarrow\)\(3x-x=-14-18\)
\(\Leftrightarrow\)\(2x=-32\)
\(\Leftrightarrow\)\(x=\frac{-32}{2}\)
\(\Leftrightarrow\)\(x=-16\)
b) Ta có :
\(\left|x+3\right|\ge0\)\(;\)\(\left|x+9\right|\ge0\) và \(\left|x+5\right|\ge0\) nên \(\left|x+3\right|+\left|x+9\right|+\left|x+5\right|\ge0\)
Mà \(\left|x+3\right|+\left|x+9\right|+\left|x+5\right|=4x\) \(\Rightarrow\)\(4x\ge0\)
Vì \(4>0\) nên \(x\ge0\)
\(\Rightarrow\)\(\left|x+3\right|+\left|x+9\right|+\left|x+5\right|=4x\)
\(\Leftrightarrow\)\(x+3+x+9+x+5=4x\)
\(\Leftrightarrow\)\(\left(x+x+x\right)+\left(3+9+5\right)=4x\)
\(\Leftrightarrow\)\(3x+17=4x\)
\(\Leftrightarrow\)\(4x-3x=17\)
\(\Leftrightarrow\)\(x=17\)
Vậy \(x=17\)
\(x-14=3x+18\)
\(x-3x=14+18\)
\(-2x=32\)
\(x=\frac{32}{-2}\)
\(x=-16\)
\(5\frac{4}{9}+x-7\frac{7}{18}=15\frac{3}{4}\)
\(\frac{49}{9}+x-\frac{133}{18}=\frac{63}{4}\)
\(\frac{49}{9}+x=\frac{833}{36}\)
\(x=\frac{637}{36}\)