Question

[BÍCH THẢO]

mik đag gấp í mn giúp mik nhé (cảm ơn )

Answer 1

[HT.Phong (9A5)]

b) \(B=\dfrac{2^{10}\cdot52+2^{12}\cdot65}{2^{11}\cdot52}+\dfrac{\left(-3\right)^{10}\cdot11+3^9\cdot15}{3^8\cdot2^3\cdot6}\)

\(B=\dfrac{2^{10}\cdot2^2\cdot13+2^{12}\cdot5\cdot13}{2^{11}\cdot13\cdot2^2}+\dfrac{\left(-3\right)^{10}\cdot11+3^9\cdot3\cdot5}{3^8\cdot2^3\cdot2\cdot3}\)

\(B=\dfrac{2^{12}\cdot13+2^{12}\cdot13\cdot5}{2^{13}\cdot13}+\dfrac{3^{10}\cdot11+3^{10}\cdot5}{3^9\cdot2^4}\)

\(B=\dfrac{2^{12}\cdot13\cdot\left(1+5\right)}{2^{13}\cdot13}+\dfrac{3^{10}\cdot\left(11+5\right)}{3^9\cdot2^4}\)

\(B=\dfrac{1+5}{2}+\dfrac{3\cdot16}{2^4}\)

\(B=3+3\)

\(B=6\)

Answer 2

[BÍCH THẢO]

cảm on bẹn nha