M=1/3+1/15+1/35+...+1/2499
GHI CÁCH GIẢI GIÙM MÌNH NHA CẢM ƠN NHÌU
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Bạn tự viết lại đề bài nha
\(\frac{1}{2}\)x\(\frac{2}{3}\)x\(\frac{3}{4}\)x\(\frac{4}{5}\)x...x\(\frac{18}{19}\)x\(\frac{19}{20}\)
=\(\frac{1x2x3x4x...x18x19}{2x3x4x5x...x19x20}\)
=\(\frac{1}{20}\)
= \(\frac{1}{2}\). \(\frac{2}{3}\).\(\frac{3}{4}\).\(\frac{4}{5}\). ... . \(\frac{18}{19}\).\(\frac{19}{20}\)
= \(\frac{1}{2}\)
tk cho mk nha, mik đg âm điểm huhu
a)
`127+246+273+354`
`=(127+273)+(246+354)`
`=400+600`
`=1000`
b)
`1,58+3,04+6,96+3,42`
`=(1,58+3,42)+(3,04+6,96)`
`=5+10`
`=15`
c)
`1/2+1/3+1/5+1/6`
`=(1/2+1/3+1/6)+1/5`
`=(3/6+2/6+1/6)+1/5`
`=6/6+1/5`
`=1+1/5`
`=5/5+1/5`
`=6/5`
a, 127 + 246 + 273 + 354
= ( 127 + 273) + ( 246 + 354)
= 400 + 600
= 1000
b, 1,58 + 3,04 + 6,96 + 3,42
= ( 1,58 + 3,42) + ( 3,04 + 6,96)
= 5 + 10
= 15
c, \(\dfrac{1}{2}\) + \(\dfrac{1}{3}\) + \(\dfrac{1}{5}\) + \(\dfrac{1}{6}\)
= ( \(\dfrac{1}{2}\) + \(\dfrac{1}{3}\) + \(\dfrac{1}{6}\)) + 0,2
= 1 + 0,2
= 1,2
\(\left(x+2\right)^2=\left(2x-1\right)^2\\ \Leftrightarrow\left(x+2\right)^2-\left(2x-1\right)^2=0\\\Leftrightarrow\left[x+2-\left(2x-1\right)\right]\left[x+2+2x-1\right]=0\\ \Leftrightarrow\left(x+2-2x+1\right)\left(x+2+2x-1\right)=0\\ \Leftrightarrow\left(-x+3\right)\left(3x+1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}-x+3=0\\3x+1=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}-x=-3\\3x=-1\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=3\\x=-\dfrac{1}{3}\end{matrix}\right.\)
\(\left(x+2\right)^2=\left(2x-1\right)^2\)
\(\Leftrightarrow\left[{}\begin{matrix}x+2=2x-1\\x+2=-\left(2x-1\right)\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x-2x=-1-2\\x+2=-2x+1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}-x=-3\\x+2x=1-2\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\3x=-1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-\dfrac{1}{3}\end{matrix}\right.\)
1/1x2 + 1/2x3 +1/3x4 + ......+1/98x99+1/99x100
=1/1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 +......+ 1/98 - 1/99 + 1/99 + 1/100
=(1-1/100)+(1/2 - 1/2 ) + ( 1/3 - 1/3 ) + ...... + (1/98 - 1/98 ) + ( 1/99 - 1/99 )
= 100/100 - 1/100 + 0 + 0 +.....+ 0 + 0
=99/100
vậy GTBT = 99/100
TH1:\(\hept{\begin{cases}x+\frac{1}{2}>0\\x-\frac{1}{3}>0\end{cases}\Leftrightarrow\hept{\begin{cases}x>-\frac{1}{2}\\x>\frac{1}{3}\end{cases}\Leftrightarrow}x>\frac{1}{3}}\)
TH2:\(\hept{\begin{cases}x+\frac{1}{2}< 0\\x-\frac{1}{3}< 0\end{cases}\Leftrightarrow\hept{\begin{cases}x< -\frac{1}{2}\\x< \frac{1}{3}\end{cases}\Leftrightarrow}x< -\frac{1}{2}}\)
vậy để biểu thức \(\left(x+\frac{1}{2}\right)\left(x-\frac{1}{3}\right)>0\)thì x > 1/3 hoặc x < (-1/2)
Ta có : M=1/3+1/15+1/35+...+1/2499
=> M=1/1.3+1/3.5+1/5.7+...+1/49.51
=>2M=2/1.3+2/3.5+2/5.7+...+2/49.51
=>2M=1-1/3+1/3-1/5+1/5-1/7+...+1/49-1/51
=>2M=1-1/51
=>2M=50/51
=> M=50/51:2
=> M=25/51
Vậy M=25/51
Mọi người tk giúp mik nha mik đang âm điểm nek !!!
k mk đi làm ơn
mk đang bị âm điểm