x+93= 93+0
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\(A=\frac{1}{0,\left(93\right)}+\frac{10}{0,\left(93\right)}+\frac{100}{0,\left(93\right)}=\frac{1+10+100}{\frac{93}{99}}=111:\frac{93}{99}=\frac{111.99}{93}=\frac{10989}{93}\)
<=> (1927-x/91 + 1)+(1925-x/93 + 1) + (1923-x/95 + 1) + (1921-x/97 + 1) = 0
<=> 2018-x/91 + 2018-x/93 + 2018-x/95 + 2018-x/97 = 0
<=> (2018-x).(1/91 + 1/93 + 1/95 + 1/97) = 0
<=> 2018-x = 0 ( vì 1/91 + 1/93 + 1/95 + 1/97 > 0 )
<=> x = 2018
Vậy x = 2018
Tk mk nha
\(\frac{1927-x}{91}+\frac{1925-x}{93}+\frac{1923-x}{95}+\frac{1921-x}{97}+4=0\)
\(\Leftrightarrow\left(\frac{1927-x}{91}+1\right)+\left(\frac{1925-x}{93}+1\right)+\left(\frac{1923-x}{95}+1\right)+\left(\frac{1921-x}{97}+1\right)=0\)
\(\Leftrightarrow\frac{1927-x+91}{91}+\frac{1925-x+93}{93}+\frac{1923-x+95}{95}+\frac{1921-x+97}{97}=0\)
\(\Leftrightarrow\frac{2018-x}{91}+\frac{2018-x}{93}+\frac{2018-x}{95}+\frac{2018-x}{97}=0\)
\(\Leftrightarrow\left(2018-x\right)\left(\frac{1}{91}+\frac{1}{93}+\frac{1}{95}+\frac{1}{97}\right)=0\)
Vì \(\frac{1}{91}+\frac{1}{93}+\frac{1}{95}+\frac{1}{97}\ne0\)\(\Rightarrow2018-x=0\)\(\Leftrightarrow x=2018\)
Vậy tập nghiệm của phương trình là \(S=\left\{2018\right\}\)
\(a,C1=744+186\\ =930\\ C2=93\times\left(8+2\right)\\ =93\times10=930\\ b,C1:=324+576\\ =900\\ C2=9\times\left(36+64\right)\\ =9\times100\\ =900\\ c,C1=456-399\\ =57\\ C2=57\times\left(8-7\right)\\ =57\)
\(a)\)\(93\times8+93\times2\)
\(=98\times\left(8+2\right)\)
\(=98\times10\)
\(=980\)
\(b)36\times9+64\times9\)
\(=9\times\left(36+64\right)\)
\(=9\times100\)
\(=900\)
\(c)57\times8+57\times7\)
\(=57\times\left(8-7\right)\)
\(=57\times1\)
\(=57\)
| x + 93 | + | -y + 17 | = 0
=> x + 93 = 0 và -y + 17 = 0
+) x + 93 = 0 => x = -93
+) -y + 17 = 0 => -y = -17 => y = 17
Vây x = -93, y = 17
x=93-93
x=0
x+93=93+0
x+93=93
=>x=0