nhờ các bn nữa nha
1) (4x+2)(x2+1)=0
2) (x-1)(2x+7)(x2+2)=0
3)(3x-2)(\(\frac{2\left(x+3\right)}{7}-\frac{4x-3}{5}\))
4) (x2+1)(x2-4x+4)=0
5) (3,3-11x)(\(\frac{7x+2}{5}+\frac{2\left(1-3x\right)}{3}\))
khổ cho các bn ghê á mik toàn nhờ các bn thui à
1.(4x+2)(x2 +1)=0
\(\Leftrightarrow\) \(\left\{{}\begin{matrix}4x+2=0\\x^2+1=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}4x=-2\\x^2=-1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\frac{-1}{2}\\x=-1\end{matrix}\right.\)
2.(x-1)(2x+7)(x2+2)=0
\(\Leftrightarrow\left\{{}\begin{matrix}x-1=0\\2x+7=0\\x^2-2=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=1\\x=\frac{-7}{2}\\x=-1,4142\end{matrix}\right.\)