Question

[Vân Nguyễn Thị]

Mọi ngừi giúp e dzới, 22h là e phải nộp ròi ah 

Answer 1

[Liah Nguyen]

a, Giả sử: Cz // Ax // By

Do Cz // Ax \(\Rightarrow\widehat{A}+\widehat{C_1}=180^o\)(2 góc TCP)

                   \(\Rightarrow80^o+\widehat{C_1}=180^o\)

                    \(\Rightarrow\widehat{C_1}=180^o-80^o=100^o\)

Do Cz // By \(\Rightarrow\widehat{C_2}=\widehat{B}=35^o\)(2 góc so le trong)

Ta thấy: \(\widehat{ACB}=\widehat{C_1}+\widehat{C_2}=100^o+35^o=135^o\)

b, Do d // AC \(\Rightarrow\widehat{ACB}+\widehat{EBC}=180^o\)(2 góc TCP)

                      \(\Rightarrow135^o+\widehat{EBC}=180^o\)

                       \(\Rightarrow\widehat{EBC}=180^o-135^o=45^o\)                       

Answer 2

[Liah Nguyen]