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a: \(=-\left(10x^2+15x-8x-12\right)=-10x^2-7x+12\)
\(3^2\cdot5+2^3\cdot10-3^4:3\\ =9\cdot5+8\cdot10-3^4\\ =45+80-27\\ =98\)
\(3^2.5+2^3.10-3^4:3\)
\(=9.5+8.10-3^3\)
\(=45+80-27\)
\(=125-27\)
\(=98\)
\(#WendyDang\)
a, (y-476)x2=2196x3
(y-476)x2=2196x2+2196
(y-476)x2-2196x2=2196
(y-476-2196)x2=2196
(y-(476+2196)x2=2196
(y-2672)x2=2196
(y-2672)x2=1098x2
(y-2672)x2-1098x2=0
(y-2672-1098)x2=0
(y-(2672+1098)x2=0
(y-3770)x2=0
y-3770=0
y=3770
ĐS: y=3770
\(60-\left[15.2+\left(4+1^{35}\right)^2\right]\)
\(\Rightarrow60-\left[30+\left(4+1\right)^2\right]\)
\(\Rightarrow60-\left[30+25\right]\)
\(\Rightarrow60-55\)
\(\Rightarrow5\)
Ta có:
\(\left(x-1\right).\left(x+1\right).\left(x+2\right)\)
\(=\left(x^2+x-x-1\right).\left(x+2\right)\)
\(=\left(x^2-1\right).\left(x+2\right)\)
\(=x^3+2x^2-x-2\)
\(\dfrac{5x+5y}{3x-3y}:\dfrac{5x}{x^2-y^2}.\)
\(=\dfrac{5\left(x+y\right)}{3\left(x-y\right)}.\dfrac{\left(x-y\right)\left(x+y\right)}{5x}.\)
\(=\dfrac{x+y}{3}.\dfrac{x+y}{x}.\)
\(=\dfrac{\left(x+y\right)^2}{3x}.\)
\(=\dfrac{4\left(\sqrt{5}+\sqrt{2}\right)}{3}+\dfrac{3\left(\sqrt{5}+2\right)}{1}-\dfrac{2\left(\sqrt{3}+2\right)}{-1}+\dfrac{\sqrt{3}-1}{6}\\ =\dfrac{8\sqrt{5}+8\sqrt{2}+\sqrt{3}-1}{6}+3\sqrt{5}+6+2\sqrt{3}+4\\ =\dfrac{8\sqrt{5}+8\sqrt{2}+\sqrt{3}-1+18\sqrt{5}+60+12\sqrt{3}}{6}\\ =\dfrac{26\sqrt{5}+8\sqrt{2}+13\sqrt{3}+59}{6}\)