Giải các phương trình sau :
a)\(\left|\dfrac{x+5}{-x^2+9}\right|=2\)
b)\(\dfrac{4}{\sqrt{2-x}}-\sqrt{2-x}=2\)
c)\(^{x^2-6x+9=4\sqrt{x^2-6x+6}}\)
d)\(\sqrt{x-3}=\dfrac{2}{\sqrt{x}-2}\)
e)\(\sqrt{x+1}=8-\sqrt{3x+1}\)
f')(x-2)\(\sqrt{2x+7}=x^2-4\)
g)\(\sqrt{x+2\sqrt{x-1}}+\sqrt{x-2\sqrt{x-1}}=x-1\)
h)\(\sqrt{x+4}-\sqrt{1-x}=\sqrt{1-2x}\)
i) \(\sqrt{x+4}-\sqrt{3x+1}+2\sqrt{3x^2+13x+4}=51-4x\)
k)\(\dfrac{x-2}{1-x}+\dfrac{x-3}{x+1}=\dfrac{x^2+4x+15}{x^2-1}\)
Câu a:
ĐKXĐ: \(x\neq \pm 3\)
\(\left|\frac{x+5}{-x^2+9}\right|=2\Rightarrow \left[\begin{matrix} \frac{x+5}{-x^2+9}=2\\ \frac{x+5}{-x^2+9}=-2\end{matrix}\right.\)
\(\Rightarrow \left[\begin{matrix} x+5=2(-x^2+9)\\ x+5=-2(-x^2+9)\end{matrix}\right.\Rightarrow \left[\begin{matrix} 2x^2+x-13=0\\ 2x^2-x-23=0\end{matrix}\right.\)
\(\Rightarrow \left[\begin{matrix} x=\frac{-1\pm \sqrt{105}}{4}\\ x=\frac{1\pm \sqrt{185}}{4}\end{matrix}\right.\) (đều thỏa mãn )
Vậy.......
Câu b:
ĐKXĐ: \(x< 2\)
Ta có: \(\frac{4}{\sqrt{2-x}}-\sqrt{2-x}=2\)
\(\Rightarrow 4-(2-x)=2\sqrt{2-x}\)
\(\Leftrightarrow 4=(2-x)+2\sqrt{2-x}\)
\(\Leftrightarrow 5=(2-x)+2\sqrt{2-x}+1=(\sqrt{2-x}+1)^2\)
\(\Rightarrow \sqrt{2-x}+1=\sqrt{5}\) (do \(\sqrt{2-x}+1>0\) )
\(\Rightarrow \sqrt{2-x}=\sqrt{5}-1\)
\(\Rightarrow 2-x=6-2\sqrt{5}\)
\(\Rightarrow x=-4+2\sqrt{5}\) (thỏa mãn)
Vậy...........