1+1-1+1-1+1-1+1-1+6+199999999999999999999999999999999999=?
Giúp mình nha
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Tính
Đặt \(Q=\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}\)
\(\Rightarrow\frac{1}{2}\times Q=\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}\)
\(=\frac{1}{2\times3}+\frac{1}{3\times4}+\frac{1}{4\times5}+\frac{1}{5\times6}+\frac{1}{6\times7}+\frac{1}{7\times8}\)
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\)
\(=\frac{1}{2}-\frac{1}{8}=\frac{4}{8}-\frac{1}{8}=\frac{3}{8}\)
\(\Rightarrow Q=\frac{3}{8}:\frac{1}{2}=\frac{3}{8}\times2=\frac{3}{4}\)
Vậy \(Q=\frac{3}{4}.\)
Ta goi day tren la A.Ta co:A=1/2+1/6+1/12+1/20+...+1/x(x+1)=2013/2014
A=1/(1*2)+1/(2*3)+1/(3*4)+...+1/x(x+1)=2013/2014
A=1-1/2+1/2-1/3+1/3-1/4+...+1/x-1/x+1.=2013/2014
A=1-1/x+1=2013/2014
Suy ra:1/x+1=1-2013/2014
1/1+1=1/2014
Suy ra x+1=2014
Suy ra x=2013
(1-1/3).(1-1/6).(1-1/10)...(1-1/780) (ko có dấu "...")
Giải: (1-1/3).(1-1/6).(1-1/10)...(1-1/780)
= 2/3 . 5/6....779/780
= 4/6 . 10/12.....1558/1560
= 1.4 . 2.5 .... 38.41/ 2.3 . 3. 4. .....39.40
= ( 1.2.3....38).(4.5....41)/(2.3.4....39)(3...
triệt tiêu xong còn 41/39.3= 41/117
ĐS = 41/117
ta có:
1/6+1/12+1/20+1/30+.........+1/90+1/110
= 1/2x3+1/3x4+1/4x5+1/5x6+....+1/9x10+1/10x11
= 1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+....+1/9-1/10+1/10-1/11
=1/2-1/11=11/22-2/22=9/22
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{10}-\frac{1}{11}\)
\(=\left(\frac{1}{2}-\frac{1}{11}\right)+\left(\frac{1}{3}-\frac{1}{3}\right)+\left(\frac{1}{4}-\frac{1}{4}\right)+...+\left(\frac{1}{10}-\frac{1}{10}\right)\)
\(=\frac{1}{2}-\frac{1}{11}=\frac{11}{22}-\frac{2}{22}=\frac{9}{22}\)
1/6 x 2 = 1/3
1/3 x 3 = 1
1 x 4 =4
4 x 5 =20
20 x 6 =120
Vậy: 1/6; 1/3; 1; 4; 20; 120
1+1-1+1-1+1-1+1-1+6+199999999999999999999999999999999999 = 200000000000000000000000000000000006
1+1-1+1-1+1-1+1-1+6+199999999999999999999999999999999999=200000000000000000000000000000000006