Tính A= (\(\dfrac{1}{2^2}\)-1) .( \(\dfrac{1}{3^2}\)-1).(\(\dfrac{1}{4^2}\)-1)....(\(\dfrac{1}{100^2}\)-1)
So sánh A= 1+\(\dfrac{1}{2^2}\)+\(\dfrac{1}{3^2}\)+\(\dfrac{1}{4^2}\)+...+\(\dfrac{1}{100^2}\) với 2
Rút gọn biểu thức D= (1-\(\dfrac{1}{2}\) ).(1-\(\dfrac{1}{3}\))....(1-\(\dfrac{1}{2015}\))
Rút gọn biểu thức A=...
Đọc tiếp
Tính A= (\(\dfrac{1}{2^2}\)-1) .( \(\dfrac{1}{3^2}\)-1).(\(\dfrac{1}{4^2}\)-1)....(\(\dfrac{1}{100^2}\)-1)
So sánh A= 1+\(\dfrac{1}{2^2}\)+\(\dfrac{1}{3^2}\)+\(\dfrac{1}{4^2}\)+...+\(\dfrac{1}{100^2}\) với 2
Rút gọn biểu thức D= (1-\(\dfrac{1}{2}\) ).(1-\(\dfrac{1}{3}\))....(1-\(\dfrac{1}{2015}\))
Rút gọn biểu thức A= \(\dfrac{3}{4}\).\(\dfrac{8}{9}\).\(\dfrac{15}{16}\).\(\dfrac{24}{25}\)...\(\dfrac{899}{900}\)
Bài 2:
Ta có: \(\dfrac{1}{2^2}< \dfrac{1}{1.2};\dfrac{1}{3^2}< \dfrac{1}{2.3};....;\dfrac{1}{100^2}< \dfrac{1}{99.100}\)
\(\Rightarrow A< 1+\dfrac{1}{1.2}+\dfrac{1}{2.3}+...+\dfrac{1}{99.100}=1+1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{99}-\dfrac{1}{100}=2-\dfrac{1}{100}< 2\)
Vậy A < 2
Bài 3:
D = \(\left(1-\dfrac{1}{2}\right).\left(1-\dfrac{1}{3}\right)....\left(1-\dfrac{1}{2015}\right)\)
\(=\dfrac{1}{2}.\dfrac{2}{3}......\dfrac{2014}{2015}\)
\(=\dfrac{1.2......2014}{2.3......2015}=\dfrac{1}{2015}\)
Bài 4:
A = \(\dfrac{3}{4}.\dfrac{8}{9}.\dfrac{15}{16}......\dfrac{899}{900}\)
\(=\dfrac{1.3}{2.2}.\dfrac{2.4}{3.3}.\dfrac{3.5}{4.4}........\dfrac{29.31}{30.30}\)
\(=\dfrac{1.2.3......29}{2.3.4.......30}.\dfrac{3.4.5......31}{2.3.4.....30}\)
\(=\dfrac{1}{30}.\dfrac{31}{2}=\dfrac{31}{60}\)