Bài 1 : Thu gọn biểu thức
a) (a-b-d)+(b-a-d)
b) -(a-b+c)-(a-b-c)
c) (c-a+d)+(a-b-d)
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a, -( -a + c - d) - ( c - d + d) = a - c + d - c + d - d = a + d
b, - ( a+b-c+d) + (a-b-c-d) = -a -b+c-d + a-b-c-d = -2b + (-2c)= -2(b+c)
a) A = ( a+ b – c + d ) – ( - a – b + c – d )
= a+ b – c + d + a + b - c + d
= 2a + 2b + 2d – 2c
b) B = ( a+ b – c ) + ( a – b ) – ( a – b - c )
= a+ b – c + a – b – a + b + c
= a + b
a) \(\left(2a-b\right)\left(b+4a\right)+2a\left(b-3a\right)\)
\(=2ab+8a^2-b^2-4ab+2ab-6a^2\)
\(=\left(2ab+2ab-4ab\right)+\left(8a^2-6a^2\right)-b^2\)
\(=2a^2-b^2\)
b) \(\left(3a-2b\right).\left(2a-3b\right)-6a\left(a-b\right)\)
\(=6a^2-9ab-4ab+6b^2-6a^2+6ab\)
\(=\left(6a^2-6a^2\right)-\left(9ab+4ab-6ab\right)+6b^2\)
\(=-7ab+b^2\)
c) \(5b\left(2x-b\right)-\left(8b-x\right)\left(2x-b\right)\)
\(=10bx-5b^2-\left(16bx-8b^2-2x^2+bx\right)\)
\(=10bx-5b^2-16bx+8b^2+2x^2-bx\)
\(=\left(10bx-16bx-bx\right)-\left(5b^2-8b^2\right)+2x^2\)
\(=-7bx+3b^2+2x^2\)
d) \(2x\left(a+15x\right)+\left(x-6a\right)\left(5a+2x\right)\)
\(=2ax+30x^2+5ax+2x^2-30a^2-12ax\)
\(=\left(2ax+5ax-12ax\right)+\left(30x^2+2x^2\right)-30a^2\)
\(=-5ax+32x^2-30a^2\)
a: =2ab+8a^2-b^2-4ab+2ab-6a^2
=2a^2-b^2
b: =6a^2-9ab-4ab+6b^2-6a^2+6ab
=-7ab+6b^2
c: =10bx-5b^2-16bx+8b^2+2x^2-xb
=3b^2+2x^2-7xb
d: =2xa+30x^2+5ax+2x^2-30a^2-12ax
=32x^2-30a^2-5ax
1: =a-b+c-a-c=-b
2: =a+b-b+a+c=2a+c
3: =-a-b+c+a-b-c=-2b
4: =ab+ac-ab-ad-ac+ad=0
a) \(\left(a-b\right)-\left(2c-4a\right)+3c\)
\(=a-b-2c+4a+3c\)
\(=5a-b+c\)
b) \(\left(12-60\right)-\left(2.-135-4.12\right)+3.-135\)
\(=-48-\left(-318\right)+\left(-405\right)\)
\(=-135\)
Bài 1:
a, A=(a-b)-(2c-4a)+3c
=a-b-2c+4a+3c
=5a-b+c
b, thay a=12; b=60; c=-135
A=5*12-60+(-135)
A=-135
Bài 2:
a, (a-b)+(c-d)-(a+c)
=a-b+c-d-a-c
=-b-d
=-(b+d) (đpcm)
b, (a-b)-(c-d)+(b+c)
=a-b-c+d+b+c
=a+d (xem lại đề bài bạn)
Chúc may mắn
a) \(\left(a-b-d\right)+\left(b-a-d\right)=a-b-d+b-a-d\)
\(=\left(a-a\right)-\left(b-b\right)-\left(d+d\right)\)
\(=0-2d\)
\(=-2d\)
b) \(-\left(a-b+c\right)-\left(a-b-c\right)=-a+b-c-a+b+c\)
\(=\left(-a-a\right)+\left(b+b\right)-\left(c-c\right)\)
\(=-2a+2b\)
c) \(\left(c-a+d\right)+\left(a-b-d\right)=c-a+d+a-b-d\)
\(=c-\left(a-a\right)+\left(d-d\right)-b\)
\(=c-b\)
a ) \(\left(a-b-d\right)+\left(b-a-d\right)=a-b-d+b-a-d=-2d\)
b ) \(-\left(a-b+c\right)-\left(a-b-c\right)=-a+b-c-a+b+c=-2a+2b=2\left(-a+b\right)\)
c ) \(\left(c-a+d\right)+\left(a-b-d\right)=c-a+d+a-b-d=c-b\)